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allochka39001 [22]
3 years ago
6

1 ) During his morning commute to work in rush hour traffic, Justin's average speed was 30 mi/h. During his afternoon commute ba

ck home along the same route, his average speed was 60 mi/h. What was his average speed for the entire round trip?
15 points, answer correctly, please!
Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0

Answer:45 mi/h

Step-by-step explanation:

Recall: Speed = distance / time

Let the time taken for the morning journey be t_{1} and the time taken for the afternoon journey be t_{1} ,and the distance covered be d

that means for the first journey,

30 = \frac{d}{t_{1}}

d = 30 t_{1}

Also for the afternoon journey,

d = 60 t_{2}

Equating the two , since the same distance is being covered , we have

30 t_{1} = 60 t_{2}

that is

t_{1} = \frac{60t_{2}}{30}

t_{1} = 2 t_{2}

Also ,

total distance covered = 30 t_{1} + 60 t_{2}

Average speed = total distance / total time

 = 30 t_{1} + 60 t_{2} / t_{1} +t_{2}

  Recall that   t_{1} = 2 t_{2} , substitute this  into the formula for average speed , then we have

Average speed = 30(2t_{2}) +60 t_{2} / 3t_{2}

Average speed = 120t_{2} / 3t_{2}

Therefore :

Average speed = 40 mi/hr

                           

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