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otez555 [7]
3 years ago
10

I need help with number 3 ASAP

Mathematics
1 answer:
jeyben [28]3 years ago
6 0
The sixth choice is the correct answer
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What is the area of the shaded region? (picture is below) pls help me :((
DedPeter [7]

Answer:

its 210

Step-by-step explanation:

area of rect is 20×12=240

tri angle area=1/2×5×12=30

so 240-30=210

HOPE THIS HELPS!!

:)

6 0
3 years ago
Read 2 more answers
Help me in math tasks please​
Ivan

Answer:

1. 3/5                        c

2. 7                           c

3. 2/5                       b

4. $3.24                   c  

5. -3.2                      b

Step-by-step explanation:

1.

2/5 + 1/5  =    3/5

2.

a negative + a negative = a positive

2+5 = 7

3.

terminating means the decimal ends. When u divide a & c they keep on going but 2/5 ends

4.

divide 16.8 by 5.19 = 3.23 round up so 3.24

5.

multiply the two together to get the answer

3 0
4 years ago
Please help? <br> What is the period? <br> A. 1440<br> B. 360
zlopas [31]
This is a, 1440!!!! :)
8 0
3 years ago
Read 2 more answers
HELP PLEASE ASAP! BRAINLIESTTTTTTTTT
guapka [62]
A fairly strong positive correlation.
6 0
3 years ago
Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)
xenn [34]

Answer:

if the sequence is:

12, 13, 13, 14, 14 etc, and each term keeps growing up, the sequence obviusly diverges.

Now, if the sequence is

1/2, 1/3, 1/3, 1/4, 1/4, 1/5 , 1/5

so the terms after the first one repeat, we could group the terms with the same denominator and get:

1/2, 2/3, 2/4, 2/5..... etc.

So the terms after the first one are aₙ = 2/n.

Now, a criteria to see if a sequence converges if seing if:

\lim_{n \to \infty} a_n = 0

and here we have;

\lim_{n \to \infty} 2/n

that obviusly tends to zero, so we can conclude that this sequence converges.

then the limit is:

There exist a n' such that for any n > n' then IL -aₙI < ε

where L is the limit

I2/n - 0I = I2/nI < ε

then this is true if n > 2/ε = n'

3 0
3 years ago
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