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2 years ago

Please help? What is the period? A. 1440 B. 360

Mathematics

2 answers:

zlopas [31]2 years ago

8 0

This is a, 1440!!!! :)

Daniel [21]2 years ago

6 0

I think it’s A but I’m not sure

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Max runs 3 laps around the track in 8 min. How many minutes per lap is that?

ICE Princess25 [194]

Answer:

Step-by-step explanation:

8/3 = 2.6666 (repeating 6)

so rounded about 2.7 minutes per lap :)

3 0

3 years ago

1-sin60÷cos60=1-Tan30÷1+Tan30

ipn [44]

Step-by-step explanation:

LHS=(1-sin60)/cos60

=(1-√3÷2)/1÷2

=2(1-√3÷2)

=2-√3

RHS=(1-tan30)/(1+tan30)

={1-(1÷√3)}/{1+(1÷√3)}

={(√3-1)/√3}/{(√3+1)/√3}

=(√3-1)/(√3+1)

={(√3-1)(√3-1)}/{(√3+1)(√3-1)}

=(3-√3-√3+1)/(3-1)

=(4-2√3)/2

=2-√3

Therefore LHS=RHS

8 0

3 years ago

How would you prove this trigonomic identity? Please show steps.

Agata [3.3K]

Start by combining the fractions:

$\dfrac{\cos\alpha}{1+\sin\alpha}\cdot\dfrac{1-\sin\alpha}{1-\sin\alpha}+\dfrac{\cos\alpha}{1-\sin\alpha}\cdot\dfrac{1+\sin\alpha}{1+\sin\alpha}$

$\dfrac{\cos\alpha(1-\sin\alpha)+\cos\alpha(1+\sin\alpha)}{(1+\sin\alpha)(1-\sin\alpha)}$

$\dfrac{2\cos\alpha}{1-\sin^2\alpha}$

Recall the Pythagorean identity:

$\dfrac{2\cos\alpha}{\cos^2\alpha}$

Then cancel a factor of $\cos\alpha$ and use the definition of secant:

$\dfrac2{\cos\alpha}=\boxed{2\sec\alpha}$

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3 years ago

Carlos deposits $400 into an account that pays simple interest at a rate of 6% per year. How much interest will he be paid in th

kobusy [5.1K]

Answer:

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Step-by-step explanation:

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2 years ago

The smallest integer that can be added to -2m3 − m + m2 + 1 to make it completely divisible by m + 1 is .

dangina [55]

Recall the polynomial remainder theorem: if $m-c$ is a factor of some polynomial $p(m)$ , then the remainder upon dividing $p(m)$ by $m-c$ is $p(c)$ .

Let $c=-1$ and $p(m)=-2m^3+m^2-m+1$ . The remainder left from dividing $p(m)$ by $m+1$ is

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If we subtract 5 from both sides, we'd get a "remainder" of 0, which suggests that we have to add -5 to $p(m)$ to make $m+1$ a factor.

4 0

3 years ago