This is the answer 9(-4-3) = -63
Answer:
2,674.14 g
Step-by-step explanation:
Recall that the formula for radioactive decay is
N = N₀ e^(-λt)
where,
N is the amount left at time t
N₀ is the initial amount when t=0, (given as 42,784 g)
λ = coefficient of radioactive decay
= 0.693 ÷ Half Life
= 0.693 ÷ 18
= 0.0385
t = time elapsed (given as 72 years)
e = exponential constant ( approx 2.7183)
If we substitute these into our equation:
N = N₀ e^(-λt)
= (42,787) (2.7183)^[(-0.0385)(72)]
= (42,787) (2.7183)^(-2.7726)
= (42,787) (0.0625)
= 2,674.14 g
The complete question in the attached figure
we have that
for c=5 and n=20------------> n*c=20*5=100
for c=2.5 and n=40------------> n*c=40*2.5=100
for c=2 and n=50------------> n*c=50*2=100
for c=1.25 and n=80------------> n*c=80*1.25=100
therefore
<span>the function that models the data is n*c=100
</span>
the answer is nc=100
440 x 10 = 4,400. Yes 4,400 is 10 times as much as 440