Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
Answer:
151
Step-by-step explanation:
Solution:
<u>Convert the fractions into improper fractions and solve.</u>
- 9 1/2 ÷ 3 7/10
- => 19/2 ÷ 37/10
- => 19/2 x 10/37
- => 19 x 5/37
- => 95/37
<u>Convert the fraction into mixed fraction (Not required):</u>
- => 95/37 = 37/37 + 37/37 + 21/37
- => 1 + 1 + 21/37
- => 2 + 21/37
- => 2 21/37
The solution to the problem is 2 21/37.
Y = x^2 - 16x + 17
-16/2 = (-8)
(-8)^2 = 64
Add 64 and subtract 64
y = x^2 - 16x + 64 + 17 - 64
y = (x - 8)^2 - 47
Answer:
35% or 35/100
Step-by-step explanation:
Gage Millar, Algebra 2 tutor
Choosing a number LESS than (not equal to 8) is 7/10 (1,2,3,4,5,6,7)
Chosing an even number is 5/10 (2,4,6,8,10)
so just multiply 7/10 x 5/10 to get 35 over 100, or a 35% chance
