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777dan777 [17]
3 years ago
15

Need answer with full work

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

Step-by-step explanation:

x^2 - 17x - 60

(x - 20)(x + 3)

x^2 + 3x - 20x - 60

x^2 - 17x - 60

(x + 20) is not one of the factors

using F.O.I.L., it would have been

x^2 + 17x - 60

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Solve the equation 5n+7=21
Simora [160]

Answer:

Hi there, I believe the answer to this equation is: 2.8

Step-by-step explanation:

Subtract 7 on both sides so

5n+7=21-7

you are left with 5n=14 you need to get n by itself so divide 5 on both sides.

5n/5 = 14/5

n=2.8

Hope this is correct :)

Have a great day

5 0
3 years ago
Read 2 more answers
HELPPP ASAP
Elena L [17]

Answer: 680.4 square feet

Step-by-step explanation:

please mark brainiest

4 0
3 years ago
A shopper purchased 4 tables and 2 chairs for $200 and 2 tables and 7 chairs for $400. What is the cost of each table and each c
I am Lyosha [343]
4t+2c=200
2t+7c=400

I will solve for c in terms of t first
4t+2c=200
2c=200-4t
c=100-2t

Then I will substitute this in for c in the second equation to make it single variable
2t+7c=400
2t+7(100-2t)=400
2t+700-14t=400
300t=12
t=25 
Tables cost $25 each

Plug t back into one of the ORIGINAL equations to find the cost of chairs
4(25)+2c=200
100+2c=200
2c=100
c=50
Chairs cost $50 each

Hope this helps! :)


6 0
4 years ago
PLEASE HELP!!
Bezzdna [24]

Answer:

y=-\dfrac{9}{40}x^2+\dfrac{441}{40}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}

Step-by-step explanation:

If a parabola has its vertex on the y-axis, then its equation is

y=ax^2+b

This parabola passes through the point R(3,9), then

9=a\cdot 3^2+b\\ \\9=9a+b

The area of the right triangle PQR is

A_{PQR}=\dfrac{1}{2}\cdot PQ\cdot QR

Find PQ and QR, if P(x_1,0),\ Q(3,0),\ R(3,9):

PQ=\sqrt{(x_1-3)^2+(0-0)^2}=|x_1-3|\\\\QR=\sqrt{(3-3)^2+(0-9)^2}=9

Now,

40.5=\dfrac{1}{2}\cdot |x_1-3|\cdot 9\\ \\90=9|x_1-3|\\ \\|x_1-3|=10\\ \\x_1-3=10\ \text{or}\ x_1-3=-10\\ \\x_1=13\ \text{or }x_1=-7

We get two possible points P_1(-7,0) and P_2(13,0).

For point P_1:\\

0=a\cdot (-7)^2+b\\ \\49a+b=0

So,

b=-49a\\ \\9=9a-49a\\ \\-40a=9\\ \\a=-\dfrac{9}{40}\\ \\b=\dfrac{441}{40}\\ \\y=-\dfrac{9}{40}x^2+\dfrac{441}{40}

For point P_2:\\

0=a\cdot (13)^2+b\\ \\169a+b=0

So,

b=-169a\\ \\9=9a-169a\\ \\-160a=9\\ \\a=-\dfrac{9}{160}\\ \\b=\dfrac{1,521}{160}\\ \\y=-\dfrac{9}{160}x^2+\dfrac{1,521}{160}

5 0
3 years ago
Among the expressions, two of them have the same result. Which are they?
Alex787 [66]
I just plugged all three of these equations into a calculator and A and C both equal 0. 

Hope this helped.
5 0
3 years ago
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