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777dan777 [17]
3 years ago
15

Need answer with full work

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

Step-by-step explanation:

x^2 - 17x - 60

(x - 20)(x + 3)

x^2 + 3x - 20x - 60

x^2 - 17x - 60

(x + 20) is not one of the factors

using F.O.I.L., it would have been

x^2 + 17x - 60

You might be interested in
Two percent of all seniors in a class of 50 have scored above 96% on an ext exam, which of the following is the number of senior
dalvyx [7]

Answer:

The number of seniors who scored above 96% is 1.

Step-by-step explanation:

Consider the provided information.

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.

Now we need to find the number of seniors who scored above 96%

For this we need to find the two percent of 50.

2% of 50 can be calculated as:

\frac{2}{100}\times50

\frac{100}{100}

1

Hence, the number of seniors who scored above 96% is 1.

6 0
3 years ago
Which equation passes through the points ( -4,1 ) (-8,13 )
Mashutka [201]

Answer:

y= = -3x -11

STANDARD FORM: 3x+y= -11

Step-by-step explanation:

4 0
3 years ago
Day 2- Real World- Midpoint
nevsk [136]

Answer:

Point of the flower garden  R ( 11, 44 )

Step-by-step explanation:

Let´s call   P (  3, 14 ) The center of the herb garden, and Q ( 7 , 29 ) the birdbath point

Differences in coordinates of these two points are:

x axis        7 - 3   = 4

y axis     29 - 14  = 15

Then the point Q ( x , y ) will be at:  Q ( 11, 44)

x axis    x = 11 because    7 + 4 = 11 means that the coordinate 7 is just halfway way between coordinates (x)  3 and 11  ( 4 above 3, and 4 below 11)

Reasoning the same way we conclude y = 44 in this case 29 is just halfway between coordinates  (y) 14 and 44 ( 15 above 14 and 15 below 44)

We can probe getting distance d₁  between P and Q  and d₂ distance between Q and R as:

d₁ = √ (7-3)² + ( 29-14)²

d₁ = √ 16 + 225

d₂ = √ (11 - 7)² +  ( 44 - 29)²

d₂ = √ 16 + 225

3 0
3 years ago
In how many ways can a
Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0
3 years ago
Use the discriminate to determine the number and the nature of the solutions of the giving equation
netineya [11]

Answer: x-1/6

Step-by-step explanation:

3 0
3 years ago
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