1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slava [35]
3 years ago
9

In this exercise we look at memory locality properties of matrix computation. Th e following code is written in C, where element

s within the same row are stored contiguously. Assume each word is a 32-bit integer.
for (I=0; I<8; I++)
for (J=0; J<8000; J++)
A[I][J]=B[I][0]+A[J][I];
References to which variables exhibit temporal locality?
Computers and Technology
1 answer:
Sonja [21]3 years ago
4 0

Answer:

Explanation:

temporal locality can be defined as: when a particular memory  is referenced or accessed several times  within a specific period of time. In the question, i think the variable that exhibit temporal locality are I, J and 0(all the variable). This is because the variable J and 0 are accessed several times within the loop. I would not have been part of it, but in the A[I][J]=B[I][0]+A[J][I], the variable "I" is also accessed in the addition. this is why it is part of the temporal locality.

You might be interested in
Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument
timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0
3 years ago
Write a static method named anglePairs that accepts three angles (integers), measured in degrees, as parameters and returns whet
padilas [110]

Answer:

The java program for the scenario is given below.  

import java.util.*;

public class Test

{

// method returning sum of all digits in the integer parameter

static boolean anglePairs(int a1, int a2, int a3)

{

   // variable to hold sum of two complementary angles

   int comp=90;  

   // variable to hold sum of two supplementary angles

   int supp=180;

   // boolean variable to hold result

   boolean result = false;

   if( (a1+a2 == comp) || (a2+a3 == comp) || (a1+a3 == comp) )

   {

       if( (a1+a2 == supp) || (a2+a3 == supp) || (a1+a3 == supp) )

           result = true;

       else

           result = false;

   }    

           // return variable result

       return result;

}

public static void main(String[] args)

{

   // method is called by passing three positive angles

   System.out.println("The pair of angles have both complementary and supplementary angles " + anglePairs(100, 80, 90) );    

}

}

OUTPUT

The pair of angles have both complementary and supplementary angles false

Explanation:

The program works as described below.

1. The method, anglePairs(), is declared as static having return type as Boolean which takes three positive integer parameters.

static boolean anglePairs(int a1, int a2, int a3)

{

}

2. The integer variable, comp, is declared and initialized to 90.

3. The integer variable, supp, is declared and initialized to 180.

4. The Boolean variable, result, is declared and initialized to false.

5. Using if-else statements, sum of two angles are compared with the variables, comp and supp.

6. If the sum of any two angles match with both, comp and supp, variables, the Boolean variable, result is assigned value true. Otherwise, result is assigned value false.

7. The value of result is returned.

8. Inside main() method, the function anglePairs() is called and three positive numerical values are passed as parameters.  The output is displayed.

9. All the above code is written inside the class Test.

10. User input is not taken since it is not mentioned in the question.

8 0
3 years ago
BRAINLIEST Which function will add a name to a list of baseball players in Python?
Tju [1.3M]

Answer: Append()

Explanation:

8 0
3 years ago
Read 2 more answers
Which of the following best explains the different between Cut and Copy? a. When you copy text you are permanently deleting it,
Vilka [71]
B. When you copy text it remains in its original location and places it on the clipboard. Cutting text removes it from its original location and places it on the clipboard

5 0
3 years ago
Read 2 more answers
What is an allocation unit?
sdas [7]
It is a unit of disk space allocation for files and directories. Hope this helps :) 
5 0
3 years ago
Other questions:
  • What happens when the computer is thrashing? quizzlet?
    12·1 answer
  • The term ________ refers to the use of a single unifying device that handles media, internet, entertainment, and telephone needs
    13·1 answer
  • Prior to the development of e-commerce, web sites primarily delivered static html pages. true
    11·1 answer
  • The unique global address for a web page or other resource on the internet is called the ________.
    7·1 answer
  • What is the duty of business to contribute to the well-being of society
    12·1 answer
  • In the well-known ____________________ attack, an attacker monitors (or sniffs) packets from the network, modifies them, and ins
    9·1 answer
  • Calculate the ERA
    6·1 answer
  • When engineers consider _____, they propose giving up a benefit of one proposed design in order to obtain a benefit of a differe
    14·1 answer
  • 4. In paragraph 7, what is the meaning of the phrase "not
    13·1 answer
  • The technique that allows you to have multiple logical lans operating on the same physical equipment is known as a.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!