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vladimir1956 [14]
3 years ago
11

What is the fraction to this equation 0.020 Pls help fast.

Mathematics
2 answers:
Komok [63]3 years ago
8 0

Answer:

1/50

Step-by-step explanation:

Step 1: Convert decimal to fraction.

Convert decimal to fraction

0.02 =

2 over 100

2

100

Step 2: Simplify.

2 over 100

2

100

=

1 over 50

1

50

Simplify, sub-step a: Reduce fraction to lowest terms.

Reduce fraction to lowest terms

2 over 100

2

100

=

( 2 ÷ 2 ) over ( 100 ÷ 2 )

2 ÷ 2

100 ÷ 2

=

1 over 50

1

50

2 is the greatest common divisor of 2 and 100. Reduce by dividing both numerator and denominator by 2.

sukhopar [10]3 years ago
4 0

Answer: 1/50

Step-by-step explanation:

0.020 = 20/1000 = 1/50

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PLEASE HELP ASAP FOR TEST
Sauron [17]
i believe the answer is C.) 0.8840
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5 0
3 years ago
Consider this three-digit sequence: 943. Is the first digit the largest or the second digit the smallest, AND, is the third digi
wolverine [178]
The sequence: 9, 4, 3

The largest number in this sequence is 9.
This is because 9 is of greatest value, being farther from 0 than the numbers 3 and 4.

The smallest number in this sequence is 3.
This is because 3 is of least value, being closer to 0 than the numbers 4 and 9.

Knowing this, we can answer the first question- "Is the first digit the largest or the second digit the smallest?"

9 is the first digit in this sequence, and it is the largest.
4 is the second digit in this sequence, and it is not the smallest. 3 is the smallest value in the sequence, but it is not the second digit.

This means that "the first digit is the largest" is the correct answer to the first question.

Even numbers result in integers, numbers without decimals/fractions, when divided by 2.

3 is an odd number, since it does not result in an integer when divided by 2.
3 is the third number in this sequence.

9 is also an odd number for the same reason.
9 is the first number in this sequence.

Knowing this, we can answer the second question- "Is the third digit even or the first digit odd?"

3 is the third digit in the sequence, and it is odd, not even.

9 is the first digit in the sequence, and it is odd.

This means that "the first digit is odd" is the correct answer to the second question.

Answers:
1) The first digit, 9, is the largest digit in the sequence.
2) The first digit, 9, is odd.

Hope this helps!
7 0
3 years ago
The length of a rectangle is twice the width. Find the width of the perimeter is 60 centimeters. Define a variable, write an equ
Andre45 [30]

The width of rectangle is 10 cm.

Step-by-step explanation:

Perimeter of rectangle = 60 centimeters

Let,

w be the width of rectangle.

The length of a rectangle is twice the width.

length of rectangle = 2w

We know that;

Perimeter = P = 2(Length+Width)

P = 2(2w+w)

Solving the Equation;

60=2(3w)\\60=6w\\6w=60

Dividing both sides by 6;

\frac{6w}{6}=\frac{60}{6}\\w=10

The width of rectangle is 10 cm.

Keywords: perimeter, rectangle

Learn more about perimeters at:

  • brainly.com/question/7419893
  • brainly.com/question/730852

#LearnwithBrainly

4 0
3 years ago
ANYONE PLEASE HELP ME IN MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS TOMORROW:(
vladimir1956 [14]

Answer:

.....................

10)=(-3)^2.x^4×2.y^2(5.x^2y^6)-7^2x^5×2y^4×2

=(9×5)x^8+2y^2+6-49x^10y^8

=45x^8+2y^2+6-49x^10y^8

=45x^10y^8-49x^10y^8

=-4x^10y^8

5 0
3 years ago
Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6
musickatia [10]

Answer:

(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

Step-by-step explanation:

In order to find the values of (x+y)^5 and (x+y)^6, you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

(x+y)^5 = \sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i = \frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5 = x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5.

(x+y)^6 = \sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i = \frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6= x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6.

5 0
3 years ago
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