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sammy [17]
3 years ago
5

Use the formula for the area of a rectangle, A = lw, where A represents the area, l represents the length, and w represents the

width.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Area = length × breadths

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20 multiplied by three
vodomira [7]

The answer is 60 because 2x3 is 6 so 20x 3 is 60

7 0
3 years ago
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If x = –3 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the e
natita [175]

Equations don't really have x intercepts, functions or curves do. They're also known as the zeros of the function.  When we set a function equal to zero we get an equation to solve, and the zeros of the function become the solutions or roots of the equation.

If a quadratic equation only has one root, that's a repeated root corresponding to a discriminant of zero.

In this example our equation is something like 2(x+3)^2=0, or expanded

2x^2+12x + 18 = 0

The discriminant d=b^2-4ac here is

d = 12^2 - 4(2)(18) = 0 \quad\checkmark


7 0
3 years ago
I need help im gonna post 3 more different questions pls answer them.
defon

Answer:

122

Step-by-step explanation:

1^6 = 1

11^2 = 121

1 + 121 = 122

<em>hope this helps</em>

7 0
3 years ago
Read 2 more answers
CAN SOMEONE EXPLAIN AND HELP ME ANSWER THIS QUESTION
Rasek [7]
I believe it has a maximum as it’s value
6 0
3 years ago
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is
anastassius [24]

Answer:

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

p_v =2*P(t_{(60)}>1.202)=0.234  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=424 represent the sample mean

s=26 represent the sample standard deviation

n=61 sample size  

\mu_o =420 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 420  

Alternative hypothesis:\mu \neq 420  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=61-1=60  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(60)}>1.202)=0.234  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

4 0
3 years ago
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