I’m Not 100% Sure, But I Would Think 13.1% Is The Answer.
Answer:
The perimeter is 109.8
Step-by-step explanation:
As we can see here, the angles of the triangles are congruent so we can say that both triangles are congruent
When two triangles are congruent, the ratio of their corresponding sides are equal
So we can get the scale factor here by looking at the sides facing each specific angle in both triangles
In the bigger triangle,
The side facing 34 degrees has a length of 30
In the smaller triangle,
The side facing 34 degree has a length of 27
So the scale factor to get the smaller from the bigger is 27/30 = 9/10 or 0.9
Likewise the side facing 51 degrees in the bigger is 40 while for the smaller, it is 36
So the ratio still stands at 36/40 = 9/10 or 0.9
In essence, the smaller triangle will have a perimeter that is 0.9 times that of the bigger
The perimeter of the bigger is simply the sum of the side lengths
We have this as;
(52 + 30 + 40) = 122
so that of the smaller would be;
122 * 0.9 = 109.8
The answer for this question is 1,100
Answer:
Please check the explanation
Step-by-step explanation:
Given the function
Given that the output = -3
i.e. y = -3
now substituting the value y=-3 and solve for x to determine the input 'x'
switch sides
Add 1 to both sides
![\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dg%5E3%5Cleft%28x%5Cright%29%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dg%5Cleft%28x%5Cright%29%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
Thus, the input values are:
![x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}](https://tex.z-dn.net/?f=x%3D-%5Csqrt%5B3%5D%7B2%7D%2B5%2C%5C%3Ax%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Cleft%281%2B5%5Ccdot%20%5C%3A2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29%7D%7B2%7D-i%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D%2C%5C%3Ax%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Cleft%281%2B5%5Ccdot%20%5C%3A2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29%7D%7B2%7D%2Bi%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D)
And the real input is:
![x=-\sqrt[3]{2}+5](https://tex.z-dn.net/?f=x%3D-%5Csqrt%5B3%5D%7B2%7D%2B5)
19 is the answer to this question
