Using equation of motion.
S = ut + (1/2)gt²
Where S = Height, t = time, g = acceleration due to gravity = 9.8 m/s²
time, t = 8 seconds
Since it was dropped from height, initial velocity, u = 0
S = 0*t + (1/2)gt²
S = (1/2)gt²
S = (1/2)*9.8*8² = 4.9 * 8 * 8 = 313.6
Therefore the ledge is 313.6 m tall.
W = 21 - 3
weight of the tree = 21 pounds - 3 pounds
The answer is 0.75 but sorry I cant show u the work I used the caculater
The first 4 multiples of 9 are: 9, 18, 27, 36
Since both lines c and b are perpendicular to line a, line c and b are parallel.
Using the two points on line b, we can count “up 5, right 5” to find the slope of line b to be 5/5 or 1.
Since line b has a slope of 1 and line c is parallel, it must also have a slope of 1.
