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svp [43]
3 years ago
9

Item 28

Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Answer:

Required equation: 366=x-30

Length of the main span of the Dames point Bridge = 396 meters

Step-by-step explanation:

Main span of the Sunshine Skyway Bridge = 366 meters        .... (1)

Let x represent the length of the main span of the Dames point Bridge.

It is given that the bridge's main span is 30 meters shorter than the main span of the Dames Point Bridge.

Main span of the Sunshine Skyway Bridge = x-30 meters     .... (2)

From (1) and (2) we get

366=x-30

Add 30 on both sides.

366+30=x-30+30

396=x

Hence, the required equation is 366=x-30 and the length of the main span of the Dames point Bridge is 396 meters.

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Answer: Mean Score = 50    Range = 31

               

Step-by-step explanation:

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Range = subtract smallest number from largest number

54 - 23 = 31

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Jeremy rides a Ferris wheel. The graph shows h, Jeremy’s height above the ground at any time during the ride. Which inequality r
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Answer:

10 \leq h\leq 50

Step-by-step explanation:

Jeremy rides a Ferris wheel. The graph shows h, Jeremy’s height above the ground at any time during the ride

Number line represents the height above the ground at any time during the ride.

the shaded part of the graph lies between 10 and 50, also we have solid dot at 10 and 50.

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3 years ago
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The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
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Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

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t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

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