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3 years ago

Factor each polynomial. check your answer. 12x^4 - 8x^3 - 4x^2

Mathematics

2 answers:

statuscvo [17]3 years ago

8 0

2x^2(3x^2-2x-1) hope this helps

tekilochka [14]3 years ago

7 0

Answer:

2x^2(3x^2-2x-1)

Step-by-step explanation:

12x^4 - 8x^3 - 4x^2

everything is a multiple of 4 so divide the whole thing by 4

12x^4 - 8x^3 - 4x^2/4= 3x^4-2x^3-1x^2

write it in disturbed form

2(3x^4-2x^3-1x^2)

now if u see we can see that the X will be same, so we also have to factor it out and 2 is the exponent that all can give

2x^2(3x^2-2x-1)

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2 years ago

A tv has height ratio 3:4. In a scale drawing the height is 4.5cm what would the width be?

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3 years ago

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Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

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2 years ago

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Ksivusya [100]

Answer:

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3 years ago