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3 years ago

Number 9 Math problem

Mathematics

1 answer:

maria [59]3 years ago

4 0

This needs more information

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4(x+3)-4=8(1/2x+1) i need to find the solution

oee [108]

You can solve this by algebraically as well as graphically. When I tried both ways I got:
solution is x= -2<span />

5 0

3 years ago

8,-1,-5,2? Which one!.............

Lunna [17]

Answer: I would say -8,-1

Step-by-step explanation:

4 0

3 years ago

Assume y varies directly with x. when y=2 2/3 when x=1/4, what is y when x=1 1/8? NEED HELP QUICK!!

snow_tiger [21]

3y=8x

Explanation:

If y varies directly with x then

y=c⋅x for some constant of variation c

If (x,y)=(14,23) is a solution to this equation, then

23=c⋅14

→c=23⋅41=83

y=83x

or (clearing the fraction)

3y=8x

7 0

2 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

The price of fast food has increased 7% in recent years. If today's price for a pizza is $14.95, how much was the original price

LenaWriter [7]

Answer:

13.90 dollars

Step-by-step explanation:

7 0

3 years ago