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34kurt
3 years ago
9

What is the diameter of a circle with a Circumference of 17.21? *​

Mathematics
2 answers:
Savatey [412]3 years ago
8 0

Answer:

d≈5.48

i hope you get an A

kkurt [141]3 years ago
3 0

Answer:

5.478113141

Step-by-step explanation:

to find diameter when you have the circumference you use the formula d=\frac{c}{pi}, so you divide the circumference by π and you get diameter, round your answer if you're asked to.

hope it helps :)

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(8-2•29) divided by 3
Nesterboy [21]

[(8 - 2 * 29)]/3

Let's solve inside the brackets first.

According to PEMDAS, multiplication gets solved before subtraction so multiply 2 * 29 in the parentheses.

[(8 - 58)]/3

Subtract 58 from 8 in the parentheses.

(-50)/3

Divide -50 by 3.

-16.667 or -16 2/3 is your answer.

4 0
3 years ago
Help please............
Vika [28.1K]

Answer:

B. 41

Step-by-step explanation:

7(4) + 13 \\ 28 + 13 \\ 41

5 0
2 years ago
Read 2 more answers
What is the average of two opposite numbers?
Kryger [21]

Answer:

0

Step-by-step explanation:

So lets imagine x as our number

Let's make an equation:

Average=\frac{x-x}{2} \\Average=\frac{o}{2} \\Average=0

So, This would mean that the average of two opposite numbers is always 0

Hope this helps!

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8 0
3 years ago
Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

6 0
3 years ago
Which of the binomials below is a factor of this trinomial? 3x2 + 18x - 21
lutik1710 [3]
I hope this helps you



3 (x^2+6x-7)


3 (x+7)(x-1)


3 0
2 years ago
Read 2 more answers
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