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BartSMP [9]
2 years ago
10

!30 POINTS! How can I use this trapezoid to prove the Pythagorean Theorem?

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0

Answer:

Pythagorean Theorem: c2 = a2 + b2

Find the area by adding the areas of the three triangles. The area of a right triangle is: A = ½bh

Two triangles are identical so you can just multiply the area of the first triangle by two: 2A1 = 2(½bh) = 2(½ab) = ab.

The total area of the trapezoid is : A1 + A2 = ab + ½c2

You multiply both sides by 2 to get rid of the ½: (a2 + 2ab + b2) = 2ab + c2

You subtract out the 2ab: a2 + b2 = c2.

Then what is left is the proof: a2 + b2 = c2

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Find the value of x in the figure given that SU = 133.<br><br> A) 7<br> B) 9<br> C) 11<br> D) 8
Alekssandra [29.7K]

Answer:

The answer is 9 (B)

Step-by-step explanation:

I got 9 because you have to plug in answer (7, 9, 11, 8) in each equation than add them both together. I first plugged in 7 for x in the equation 9x-5. I got 58. I plugged in 7 for x in the equation 5x+12 and got 47. When I added both the answers together I got 105. The answer was to low because SU has to be 133. I plugged in 9 for x in both equations then added them both and got 133 for SU. I hope this helps.

4 0
3 years ago
Read 2 more answers
The linear function f(x) = 0.9x + 79 represents the average test score in your math class, where x is the number of the test tak
Levart [38]

Given:

The linear function for average test score in your math class is

f(x)=0.9x+79

where x is the number of the test taken.

The linear function g(x) in the given table represents the average test score in your science class, where x is the number of the test taken.

To find:

Part A: The test average for your math class after completing test 2.

Part B: The test average for your science class after completing test 2.

Part C: Which class had a higher average after completing test 4?

Solution:

Part A:

We have,

f(x)=0.9x+79

Put x=2 in the above function, to find the test average for your math class after completing test 2.

f(2)=0.9(2)+79

f(2)=1.8+79

f(2)=80.8

Therefore, the test average for your math class after completing test 2 is 80.8.

Part B:

From the given table it is clear that g(x) =79 at x=2.

Therefore, the test average for your science class after completing test 2 is 79.

Part C:

Put x=4 in f(x), to find the test average for your math class after completing test 4.

f(4)=0.9(4)+79

f(4)=3.6+79

f(4)=82.6

From the table it is clear that the value of g(x) is increased by 1 as x is increased by 1. So, the value of function g(x) at x=4 must be 1 more than 80.

g(4)=81

It is clear that,

82.6>81

Therefore, math class had a higher average after completing test 4.

3 0
3 years ago
How long is a wire reaching from the top of a 12-foot pole to a point 6 feet from the base of the pole?
miskamm [114]
<span> Using Pythagoras' theorem it is 6 times the sq rt of 5 which is about 13.416 </span><span>feet to 3 decimal places  </span>
8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!!!
Vesna [10]

(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =

= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}

= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}

= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}

= 2^{-16-12+28} \times 5^{10-8}

= 2^{0} \times 5^{2}

= 1 \times 25

= 25

7 0
3 years ago
(Brainliest to the person that get its right)
oksian1 [2.3K]
<h3>Answer: Choice B</h3>

c^2-2cd+d^2 = (c-d)^2

We can verify this with the following steps

(c-d)^2 = (c-d)(c-d)

(c-d)^2 = c(c-d) - d(c-d)

(c-d)^2 = c^2-cd-cd+d^2

(c-d)^2 = c^2-2cd+d^2

6 0
2 years ago
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