1. a single standard number cube is rolled, what is the probability of getting 4 or 5?

1 answer:

5 0

There are 6 sides on a standard number cube. Numbers are listed on it from 1-6. This being said, 4 and 5 together make up 2/6 of the cube. Since this fraction can be reduced, this leaves us with C. 1/3

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asambeis [7]

Answer:

Linear functions can be represented by a straight line, with an intercept and a constant slope. They are formed by a dependent varible (y) and an independent varible (x) whose power equals one, which means that y is related to x in a linear way (they have both power equal to one).
The general equation of a linear function can be written as follows: y= a + b x, with a equal to a constant known as the intercept, and b equal to the slope.
We can rewrite the equations you have attached as follow, by rearranging terms in order to clear y as a function of x (in order):

$y=-19+\frac{1}{2}x$ , is a linear function: y is linked to x in a linear way, the curve has the form y= a + b x, where a=-19 and b=1/2.
$y=\frac{1}{3} x^{2}$ , it is NOT a linear function, because y is linked to x in a way that is not linear (the power of x is different from zero, in this case the power of x equals 2 ), and the graph of this expression would not be linear.
$y=\frac{1}{39}x +\frac{5}{13}$ is a linear function: y is linked to x in a linear way (the power of x equals one), the curve in this case has the form y= a + b x, where a=1/39 and b=5/13.
$y=x+\frac{25}{5}$ is a linear function: y is linked to x in a linear way (the power of x equals one), and the curve has the form y= a + b x, where a=25/5 and b=1.
$y=\sqrt[3]{x}$ is NOT a linear function, because y is linked to x in a nonlinear way, specifically, y is linked to the squared root of x, which means that is linked to $x^{\frac{1}{3} }$ , then x has not power equal to one in this case.