The answer is 90, 25, 155, 115 respectively
Answer:= 261.905% increase
Solution:
Calculate percentage change
from V1 = 21 to V2 = 76
(V2−V1)|V1|×100
(V2−V1)|V1|×100
=(76−21)|21|×100
=(76−21)|21|×100
=5521×100
=5521×100
=2.61905×100
=2.61905×100
=261.905%change
=261.905%change
=261.905%increase
I believe the answer 30,164.4
you multiply 19.95 by 3 and you get 59.85
then you figure out how many hours are from 9 am to 9 pm which was 12 then you multiply that by 6 then you take 59.85 and multiply that by 72 then you multiply that by 7
Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
Answer:
Jan 5, 2017 - A set of face cards contains 4 Jacks, 4 Queens, and 4 Kings. Carlie chooses a card from the set, records the type of card, and then replaces the card. She repeats this procedure a total of 60 times. Her results are shown in the table. How does the experimental probability of choosing a Queen
Step-by-step explanation:
