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kompoz [17]
3 years ago
5

At the lowest price for jeans, consumers will demand the _____ jeans, and producers supply the _____ jeans.

Mathematics
2 answers:
bixtya [17]3 years ago
7 0

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

At the lowest price for jeans , consumer will demand the most jeans.

As the relationship between the demand and price is inversely related.

At the lowest price for jeans, producer supply the least jeans.

As the relationship between the supply and price is directly related.

Hence, At the lowest price for jeans, consumers will demand the <u>most </u>jeans, and producers supply the <u>least</u> jeans.  

Hence, Second option is correct.

Triss [41]3 years ago
3 0
Least and most i assume
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What is this answer? I have no idea. pls help :( will give brainliest
Artist 52 [7]
The answer is B.

Negative numbers are to the far left if you were using a number line, so -1 to the 3rd power is -1. Everything else is positive. 1/4 is the same as 0.25 which is less than positive 1, positive 8.8 is next and the last would be -5 to the 2nd power which is 25.
5 0
3 years ago
A baseball coach bought some bats and gloves for the school's baseball team. The bats cost $20 to $35, and the gloves cost $30 t
Nataly_w [17]
<span>find the range. [15(35)]+[12(60)] and this will be your high end. now do it again but at the low end [15(20)]+[12(30)] and this will be your low end. now you have the max amount the price would be and the lowest amount of the price. now look at your answers and see what is within that range and what isn't and there's your answer.</span>
3 0
3 years ago
Read 2 more answers
Which two values of x are roots of the polynomial below? x^2-3x+5
Gemiola [76]

Given:

Polynomial x^2-3x+5

To find:

The values of x.

Solution:

x^2-3x+5=0

Quadratic equation formula:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here a=1, b=-3, c=5.

Substitute the values in the formula, we get

$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}

$x=\frac{3 \pm \sqrt{9-20}}{2}

$x=\frac{3 \pm \sqrt{-11}}{2}

$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}

Option E and option F are the roots of the polynomial.

The values of x are x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}.

7 0
3 years ago
HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

5 0
3 years ago
37.26 m +2.7 m + 0.0015=
Stells [14]
Add the two values being multiplied by m
37.26 + 2.7 = 39.96
39.96 m + 0.0015 is the most simplified you can get without having a way of finding the value of m. I apologize if I am mistaken, but I'm fairly certain! :)
7 0
3 years ago
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