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kompoz [17]
3 years ago
5

At the lowest price for jeans, consumers will demand the _____ jeans, and producers supply the _____ jeans.

Mathematics
2 answers:
bixtya [17]3 years ago
7 0

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

At the lowest price for jeans , consumer will demand the most jeans.

As the relationship between the demand and price is inversely related.

At the lowest price for jeans, producer supply the least jeans.

As the relationship between the supply and price is directly related.

Hence, At the lowest price for jeans, consumers will demand the <u>most </u>jeans, and producers supply the <u>least</u> jeans.  

Hence, Second option is correct.

Triss [41]3 years ago
3 0
Least and most i assume
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Will the product of two positive numbers be positive or negative? Why?
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What is the slope of the graph?
Nookie1986 [14]

Answer: The slope is \frac{3}{5}

Step-by-step explanation:

The slope of a line can be calculated with the following formula:

m=\frac{y_2-y_1}{x_2-x_1}

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4 0
3 years ago
Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably infinite, exhib
anzhelika [568]

Answer:

a) Countably infinite

b) Countably infinite

c) Finite

d) Uncountable

e) Countably infinite

Step-by-step explanation:

a) Let S the set of integers grater than 10.

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(10+k)=k-1 for k\in\mathbb{Z}^+/\{0\}.

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b) Let S the set of odd negative integers

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(-(2k+1))=k.

Let's see that the function is one-to-one.

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c) The integers with absolute value less than 1,000,000 are in the intervals A=(-1.000.000, 0) B=[0, 1.000.000). Then there is 998.000 integers in A that satisfies the condition and 999.000 integers in B that satifies the condition.

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e) Let S the set A×Z+ where A={2,3}

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(2,k)=2k, \;f(3,j)= 2j+1

Let's see that the function is one-to-one.

Consider three cases:

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2. f(3,k)=f(3,j), then 2k+1=2j+1, then 2k=2j, thus k=j.

3.  f(2,k)=f(3,j), then 2k=2j+1. But this is impossible because 2k is an even number and 2j+1 is an odd number.

Then we conclude that the correspondence is one-to-one.

6 0
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