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babymother [125]
3 years ago
8

A river 3m deep and 40 m wide is flowing at the rate 2km /h . how much water will fall into the sea in a minute.​

Mathematics
2 answers:
Alex3 years ago
8 0

Answer:

Area of river = 3 × 40

= 120 {m}^{2}

amount of water that falls into the sea ⇒

= Area × rate

= 120 × 2 \frac{km}{hr}

= 120× \frac{2000  m}{60  min}

= 2 × 2000

= 4000 m  ^{3}

∴4000m  ^{3} of water falls into the sea permin.

Step-by-step explanation:

Hope it is helpful...

Serga [27]3 years ago
3 0

Answer:

Area of river = depth × width

=3×40

= 120 {m}^{2}

amount of water that falls into the sea ⇒

Area of river × flow rate

120 {m}^{2}  \times 2 \:  \frac{km}{hr}

120 \times  \frac{2 \times 1000 {m}^{2} }{(60)min}

4000 \:   \frac{ {m}^{3} }{min}

:. {4000m}^{3} of water falls into the sea per min.

So, {4000m}^{3}

= 4000 × 1000 litres

= 4000000 litres

So, in 1 minute, water will fall into the sea is 4000000 litres.

Step-by-step explanation:

Hope it is helpful....

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Suppose you have been on the train for at least 5 hours. A passenger
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Answer:

h \leq 5

Step-by-step explanation:

Time already spent on the train is at least 5 hours

Since the trip to Fairbanks take 10 hours, we have that, the sum of the number of hours left, h and the time already spent will be equal to 10.

t+h=10\\$Since the time for which the passenger has been on the train \geq 5\\5+h \leq 10\\h \leq 10-5\\$The inequality that describes in how many more hours, h the train will reach Fairbanks, therefore, is:\\h \leq 5

4 0
3 years ago
What is a graph of a quadratic equation called
Mazyrski [523]

Answer:

Probably a parabola

Step-by-step explanation:


6 0
3 years ago
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16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x
Morgarella [4.7K]

Answer:

Foci (0,\pm\frac{\sqrt{17}}{4})

Vertices:(0,\pm 1)

Eccentricity, e=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{1}{8}

Step-by-step explanation:

We are given that

y^2-16x^2=1

y^2-\frac{x^2}{(\frac{1}{4})^2}=1

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

y^2/a^2-x^2/b^2=1 (Along y-axis)

We get

a=1, b=1/4

a^2+b^2=c^2

1+\frac{1}{16}=c^2

\frac{16+1}{16}=c^2

c^2=\frac{17}{16}

c=\pm \frac{\sqrt{17}}{4}

Therefore,

The coordinates of foci=(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})

The coordinated of vertices=(0,\pm a)=(0,\pm 1)

Eccentricity, e=c/a

e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{2b^2}{a}

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3 years ago
A pile of 37 coins consists of nickels and dimes. The total value
tensa zangetsu [6.8K]

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25 dimes & 12 nickels

Step-by-step explanation:

Let there be "n" nickels and "d" dimes

Total, there are 37 of them, so we can write:

n + d = 37

Also, valueof nickel is 0.05 and value of dime is 0.10 (in dollars) and total value of these 37 coins is 3.10, so we can write:

0.05n + 0.10d = 3.10

Now we can write first equation as:

n + d = 37

n = 37 - d

Replace this into equation 2 and solve for d:

0.05n + 0.10d = 3.10

0.05(37 - d) + 0.10d = 3.10

1.85 - 0.05d + 0.10d = 3.10

0.05d = 3.10 - 1.85

0.05d = 1.25

d = 1.25/0.05

d = 25

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There are 25 dimes & 12 nickels

7 0
4 years ago
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Really need help like help on mat​
Furkat [3]

1.<em> no solution</em>

2.<em> one solution</em>

3.<em> infinitely many solutions</em>

4. <em>infinitely many solutions</em>

5.<em> no solution</em>

6.<em> one solution</em>

7 0
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