The average rate of change of h(x) in the closed interval [ a, b ] is
Here [a, b ] = [ - 2, 2 ], thus
f(b) = f(2) = × 2³ - 2² = 1 - 4 = - 3
f(a) = × (- 2)³ - (- 2)² = - 1 - 4 = - 5
average rate of change = = =

X= lbs Abbys dog weighs
so you would take 18 divide by 2 which is 9, then you add 2. So Abbys dog weighs, 11 lbs.
Answer:
maybe 3.6?? i dont exactly know what the absolute deviation for 3 is but i have the standard deviation
Step-by-step explanation:
sorry
Area = width * length
if width = 3/8 length ⇒ length = 8/3 width
area = width * 8/3 width = 8/3 width² = 6
width² =

width =