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3 years ago

14

An architect wants to measure an angle on a set of blueprints. What tool should he use A yard stick B compass C protractor D rul

er

2 answers:

nekit [7.7K]3 years ago

7 0

You would use a ruler.

Jet001 [13]3 years ago

3 0

the correct answer is ruler

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The local amusement park was interested in the average wait time at their most popular roller coaster at the peak park time (2 p

hichkok12 [17]

Answer:

(D) 112

Step-by-step explanation:

First step: Arrange all the numbers from in ascending order that is from smallest to largest.

In Ascending order the set becomes:

45,99,108,116,118,118,118,119,120,121,124,130,148.

Second step: Find the median of the set of numbers.

Median is the middle number.

The median is 118. The median is also called the second quartile(Q2).

Third step: Now we consider all the numbers to the Left of the median(Q2). The numbers are listed below:

45,99,108,116,118,118.

Now we will find the median of these numbers.

The total numbers are 6 which is an even number.

To find the median of an even number, we add the two middle numbers and divide them by 2.

The two middle numbers are 108 and 116.

Therefore 108+116 = 224.

224/2 =112.

Therefore 112 becomes the first quartile (Q1).

4 0

3 years ago

Patrick saved 500$. He received 25% of the money for his birthday , saved 30% of the remainder from his allowance and earned the

mixer [17]

Answer: $262.50

Step-by-step explanation:

25% of 500=125

500-125= 375

30% of 375= 112.5

375-112.5= 262.5

So, the answer is $262.50

7 0

3 years ago

Construct a confidence interval of the population proportion at the given level of confidence. x = 125, n = 250, 90 % confidence

madam [21]

Answer: 90% confidence interval would be (0.448, 0.552).

Step-by-step explanation:

Since we have given that

x = 125

n = 250

So, $\hat{p}=\dfrac{x}{n}=\dfrac{125}{250}=0.5$

We need to find the 90% confidence interval.

so, z = 1.64

So, interval would be

$\hat{p}\pm z\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.5\pm 1.64\sqrt{\dfrac{0.5\times 0.5}{250}}\\\\=0.5\pm 0.0519\\\\=(0.5-0.0519,0.5+0.0519)\\\\=(0.448,0.552)$

Hence, 90% confidence interval would be (0.448, 0.552)

3 0

4 years ago

In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who

Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0

3 years ago

Does anyone know this?

Phantasy [73]

Answer:

what site is this on?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers