The area of the sector (As) of a circle may be calculated by the formula,
As = (a / 360) x π x r²
where a is the measure of angle in degrees and r is the radius. Substituting the known values,
As = (18 / 360) x 3.14 x (4²) = 2.512
Thus, the area of the sector is approximately 2.512 squared units.
To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Concentric circles because if a line is tangent to one circle, it would only intersect teh other
Answer:
132 cm squared
Step-by-step explanation:
6x5=30
6x5=30
6x8=48
1/2(8x3)=12
1/2(8x3)=12
Total added together is 132 cm squared
34992/81 or 81*x=34992 = 432
