Answer: 0.129J(gioc)
Explanation:
The basic formula for specific heat is Q=MC∆t, where m is the mass, C is the specific heat, and ∆t is the change in temperature.
The parameters given are Q= 3000j = 3kj, mass is 0.465 and ∆t is (100-50)= T2-T1
By imputing them we have;
Q=MC∆T
30= 0.465xCx(100-50)
3=23.25C
C= 3/23.25
=0.129J(gioC
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