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almond37 [142]
3 years ago
8

Why doesn't peppermint improve your reaction?

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
6 0
The myth that peppermint makes you smarter, is false, but there are benefits to the scent of peppermint. Although, eating peppermint flavored candies is not as beneficial as actually smelling the peppermint before the test.

Peppermint in many forms such as tea, candy, and oil can be used to help improve mental awareness. The menthol “stimulates the Hippocampus area of the brain which controls mental clarity and memory. The odor triggers you to wake up and pay attention.” This explains why many people believe that peppermint makes you smarter, when really it makes you more alert.

Peppermint also has the ability to improve athletic performance as well as helping to improve reaction times.

Overall, peppermint can improve your mental awareness but, no, it does not actually make you smarter.


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Calculate the concentration of acetic acid and acetate ion in a 0.2 M acetate buffer at pH 5. The p K a of acetic acid is 4.76
Levart [38]

Answer:

[Acetic acid] = 0.07 M

[Acetate] = 0.13 M

Explanation:

pH of buffer = 5

pKa of acetic acid = 4.76

pH=p_{Ka} + log\frac{[Salt]}{[Acid]}

Now using Henderson-Hasselbalch equation

5=4.76 + log\frac{[Acetate]}{[Acetic\;acid]}

log\frac{[Acetate]}{[Acetic\;acid]} = 0.24

\frac{[Acetate]}{[Acetic\;acid]} = 1.74  ....... (1)

It is given that,

[Acetate] + [Acetic acid] = 0.2 M     ....... (2)

Now solving both the above equations

[Acetate] = 1.74[Acetic acid]

Substitute the concentration of acetate ion in equation (2)

1.74[Acetic acid] + [Acetic acid] = 0.2 M

[Acetic acid] = 0.2/2.74 = 0.07 M

[Acetate] = 0.2 - 0.07 = 0.13 M

5 0
3 years ago
WILL GIVE BRAINLIEST - A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?
Hitman42 [59]

Answer:

The answer is 1 x 10 - 11 M.  :))

4 0
3 years ago
A student must use 220 mL of hot water in a lab procedure. Calculate the amount of heat required to raise the temperature of 220
Inessa [10]

Answer:

64,433.6 Joules

Explanation:

<u>We are given</u>;

  • Volume of water as 220 mL
  • Initial temperature as 30°C
  • Final temperature as 100°C
  • Specific heat capacity of water as 4.184 J/g°C

We are required to calculate the amount of heat required to raise the temperature.

  • We know that amount of heat is calculated by;

Q = mcΔT , where m is the mass, c is the specific heat, ΔT is the change in temperature.

Density of water is 1 g/mL

Thus, mass of water is 220 g

ΔT = 100°C - 30°C

    = 70°C

Therefore;

Amount of heat, Q = 220g × 4.184 J/g°C × 70°C

                               = 64,433.6 Joules

Thus, the amount of heat required to raise the temperature of water is 64,433.6 Joules

7 0
3 years ago
Could you have identified a physical property of a substance before you performed the activity? Explain.
sasho [114]

You could identify a physical property of a substance before you performed the activity because the characteristics of a material known as its physical qualities are those that may be investigated independently of the substance's chemical makeup.

This is further explained below.

<h3>What is physical property?</h3>

Generally, Any attribute that can be measured and has a value that can be used to describe the state of a physical system is considered to be a physical property.

In conclusion, The changes that take place in a system's physical attributes may be utilized to provide a description of the transitions that take place between its momentary states.

Read more about physical property

brainly.com/question/18327661

#SPJ1

8 0
1 year ago
30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter
mihalych1998 [28]
First, calculate the number of moles of sodium present with the given mass,

              31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

           mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
                  mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.
                
                 volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
                     volume of H2 = 15.34 L

Answer: 15.34 L
3 0
4 years ago
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