$(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant \frac{3}{4} \\ x \geqslant \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant \frac{3}{4} \\x \leqslant \frac{1}{2} \end{cases} \\ \Leftrightarrow x \geqslant \frac{3}{4} \: \vee \: x \leqslant \frac{1}{2} \\ \Rightarrow The\: third\: option$

5 0

3 years ago

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the ratio of the number of adults to the number of students at the prom has to be 1:10 lat year there were 477 more students tha

maksim [4K]

You would divide 10 into 477 to get 47.7, but you can't put 47.7 because you can't have a decimal. The answer is 47

8 0

3 years ago

Please I need x and y

Kryger [21]

It could be anything they are both variables.

3 0

3 years ago