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-BARSIC- [3]
3 years ago
13

Evaluate y^2 + 2y for y = 0, 1, and 2. Are the resulting numbers prime or composite.

Mathematics
1 answer:
Elza [17]3 years ago
5 0
Y = 0:
(0)^2+2(0)=0+0=0
0 is neither prime nor composite.

y=1:
(1)^2+2(1)=1+2=3
3 is a prime number (because only 3 and 1 divide evenly into it)

y = 2:
(2)^2+2(2)=4+4=8
8 is a composite number (because multiple different numbers divide evenly into it: 1, 2, 4, and 8)
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3 years ago
Solve -3y + 14 + y = 12
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Answer:

y = 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

-3y + 14 + y = 12

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms [Addition]:                                                                        -2y + 14 = 12
  2. [Subtraction Property of Equality] Subtract 14 on both sides:                       -2y = -2
  3. [Division Property of Equality] Divide -2 on both sides:                                y = 1
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Teacher's salaries in Georgia are normally distributed with an average salary of $52,000 with a standard deviation of $12,000. W
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Answer:

81.85%

Step-by-step explanation:

We have the following information:

mean = m = 52000

standard deviation = sd = 12000

a = 40000

b = 76000

we need to find the probability between a and b, that is:

P (a <x <b) = P (40,000 <x <76000)

P [(40000 - m) / sd <(x - m) / sd <(76000 - m) / sd]

replacing

P [(40000 - 52000) / 12000 <z <(76000 - 52000) / 12000]

P (-1 <z <2)

P (z <= -1) - P (z <= 2)

We look for this value of z, in the attached table:

0.9772 - 0.1587

P = 0.8185

In other words, the probability is 81.85%

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