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2 years ago

6

If it is 19 degrees out what would be the temp if it dropped 17 degrees?

2 answers:

Elis [28]2 years ago

7 0

It would be 2
19-17= 2

kvv77 [185]2 years ago

6 0

Answer:

2

Step-by-step explanation:

19 minus 17 equals 2 .

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I thought of a number, I added 1 3 4 to it, then I multiplied the result by 2 2 11 and I got 8. What was my number?

Valentin [98]

Given:

In a number, adding $1\dfrac{3}{4}$ , then multiplying the result by $2\dfrac{2}{11}$ we get 8.

To find:

The unknown number.

Solution:

Let the unknown number be x.

According to the question,

$(x+1\dfrac{3}{4})\times 2\dfrac{2}{11}=8$

$(x+\dfrac{1\times 4+3}{4})\times \dfrac{2\times 11+2}{11}=8$

$(x+\dfrac{4+3}{4})\times \dfrac{22+2}{11}=8$

$(x+\dfrac{7}{4})\times \dfrac{24}{11}=8$

Multiply both sides by $\dfrac{11}{24}$ .

$x+\dfrac{7}{4}=8\times \dfrac{11}{24}$

$x+\dfrac{7}{4}=\dfrac{11}{3}$

Subtract $\dfrac{7}{4}$ from both sides.

$x=\dfrac{11}{3}-\dfrac{7}{4}$

$x=\dfrac{44-21}{12}$

$x=\dfrac{23}{12}$

$x=1\dfrac{11}{12}$

Therefore, the required number is $1\dfrac{11}{12}$ .

3 0

2 years ago

Round 12,351 to the nearest hundred

Basile [38]

The answer to the question is 12,400

3 0

3 years ago

HELP! Writing a Two-Column Proof

torisob [31]

Answer:

1. <ABC≅ <DEF - given

2. <GHI≅<DEF- given

3. <DEF≅<GHI- Symmetric property

4. <ABC≅<GHI- transitive property

5. m<ABC=m<GHI- definition of ≅ angles

Step-by-step explanation:

5 0

2 years ago

Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.

rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed as:

$y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}$

Thus, the area of the surface is as follows:

$\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA$

$= \iint_D \sqrt{x^2 +y^2 +1 } \ dA$

$= \int^{2 \pi}_{0} \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr \ d \theta$

$=2 \pi \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr$

$= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0$

$= 2 \pi \times \dfrac{1}{3} \Bigg [ (37)^{3/2} - 1 \Bigg]$

$= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]$

3 0

2 years ago

What is the area of a quadrilateral with vertices at (-2, - 6),

svet-max [94.6K]

Answer:

18 sq. unit

you can draw it on no. line

actually it's rectangle with l=3 and b=6

4 0

2 years ago