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3 years ago

13

X/6.4=4 solve for X it’s for pre al 8th grade

1 answer:

sergeinik [125]3 years ago

8 0

Answer: x=25.6

Step-by-step explanation:Look at pic to see how it is solved.

Times 6.4 on both sides which gives you 25.6 .

You might be interested in

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .

5 0

3 years ago

There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter. To the nearest inch, how many inches are in 2 meters

AlekseyPX

Answer:

79 inches

Step-by-step explanation:

2 m * 100cm/m * 1 in/2.54cm = 78.7401574803 in

rounded

79 inches

7 0

3 years ago

Find all unknown measures

Marta_Voda [28]

Answer:

Line AC is 9.01 cm

Angle A is 33.7

Angle C is 56.3

Step-by-step explanation:

4 0

3 years ago

AYOOO PLZ HELP ASAP!!!

tamaranim1 [39]

Answer:

B.

Step-by-step explanation:

Well we know that

$224=2^{5} *7$

so we can get the 2 outside of the radical

$x^{11} =(x^{5} )^{2} *x$

and we can get the x^2 outside too.

$y^8=y^5*y^3$

and we also can get y outside.

so we have:

$2x^{2}y\sqrt[5]{7xy^3}$

7 0

2 years ago

A flagpole is 12 feet tall. Its shadow is 14 ft long. How far is it from the top of the

Kisachek [45]

Answer:

Step-by-step explanation:

AC = length of flagpole = 12 ft

AB = length of shadow = 14 ft

BC = length from the top of the flagpole to the end of the shadow = x ft

Use Pythagorean theorem to find the length of x,

x² = AC² + BC²

= 12² + 14²

= 144 + 196

= 340

x = √340

x = 18.4 ft

3 0

2 years ago