2.8 40 divided by 0.07 = 2.8 do you not have a calculator lol
Isolate the variable by dividing each side by factors that don't contain the variable.
a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}
Solve for b by simplifying both sides of the equation then isolating the variable.
b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }
Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
Answer:
The length of the transverse axis is 16.
is a focus of the hyperbola (0,17)
A vertex of the hyperbola is located at (0,8)
Step-by-step explanation:
You have the answer correct