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julia-pushkina [17]
3 years ago
14

Solve the following system of equations and show all work. y = 2x2 y = −3x −1

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
2*2 is 4, so y=4. Knowing this, the second equation is 4=-3x-1. Add 1 to each side to get 5=-3x, then divide each side by -3 to get x=-5/3
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Simplify 4 3 square root 64
Ierofanga [76]

Answer:

\large\boxed{4\sqrt[3]{64}=16}

Step-by-step explanation:

\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64

8 0
3 years ago
Express as a product In y^16
bezimeni [28]
Nbvcghnm, fdfvbvcfdcfffccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
7 0
3 years ago
Which two equations are parallel?
Mekhanik [1.2K]

Answer: The third option is correct.

Step-by-step explanation:

In order for two equations to be parallel, the equations' slopes must be the same.

5 0
2 years ago
Which option lists am expression that is not equivalent to 4^2/3
Vesnalui [34]

remember that

x^{\frac{a}{b}}=\sqrt[b]{x^a}

also x^{-a}=\frac{1}{x^a}

and (a^b)^c=a^{bc}


so

4^{\frac{2}{3}}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so 0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=  \frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}, which matches

3rd one, \sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}, which matches

4th one (\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}} which matches


answer is 0.25^{\frac{2}{3}}

4 0
3 years ago
How come the tutors don't work??​
joja [24]

Answer:

What do you mean? If you are talking about the Community not always answering Questions well that means your they don't know the right Answer

the Mods are Annoying and very skeptic of the Guidelines of Brainly.

5 0
3 years ago
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