Mary's house is approximately 49.73 miles from her grandmother's house.
The distances the three drove were;
Mary drove for 49.73 miles, Theo drove 50 miles and Nancy drove 53.299 miles.
Explanation:
- The given triangle has a 13 mile long adjacent side, a 48 mile long opposite side and the distance of Mary's route is the hypotenuse. As we have two sides of the triangle, we can solve for the length of the other side by using Pythagoras' theorem.
- Assume the hypotenuse of the triangle measures x miles. According to Pythagoras theorem, x = √(13² + 48²) , x = √169 + 2,304 x = √2,473 = 49.729. Rounding this off, we get Mary's route was 49.73 miles long.
- Nancy drove √2,840 miles = 53.2916 miles.
- So Mary drove the shortest distance of 49.73 miles, second shortest was Theo who drove for 50 miles and the longest was Nancy who drove for 53.299 miles.
Answer: 5
Step-by-step explanation:
Given : Total Material = 4 and yards
yards
Material required for each scarf =
Number of scarfs she make with the existing material
= Total Material ÷Material required for each scarf
Hence, the number of scarves can she make with the existing material = 5
Answer:
your answer is b 5784/9999
The polynomials which, when added to the polynomial 3x²+3x-1, is equivalent to the following expressions: 1, 2x²-3, and x+5 are respectively;
- P = 2 - 3x² -3x.
- P = -2 -x² -3x
- P = 6 -2x -3x².
<h3>Addition of polynomials</h3>
For the expression; 1; we have;
P = 2 - 3x² -3x.
For the expression; 2x²-3; we have;
P = -2 -x² -3x
For the expression; x +5; we have;
P = 6 -2x -3x².
Read more on Polynomial;
brainly.com/question/2833285
<u>Given</u>–
AB = 12 Cm
CD = 14 Cm
PO = 10 Cm
AP = 1/2 × 12 = 6 Cm
<u>Construction</u>–
Draw NO such that it is the perpendicular bisector of CB.
Hence,
ND = 1/2 × 14 = 7 Cm
To Find,
Measure of NO
<u>Solution</u>,
Here, PO Perpendicular to AB
Hence, APO is a right-angled triangle–
AO² = PO² + AP²
Or, AO² = 10 ² + 6 ²
Or, AO² = 36 + 100
Or, AO = √136 Cm
Or, AO = 11.66 Cm
Also, AO = OD = 11.66 Cm
( Radius of the same circle )
Now, in triangle OND,
OD² = ON² + ND ²
Or, 11.66 ² = ON² + 7²
Or, 136 = ON² + 49
Or, ON ² = 136 – 49
Or, ON ² = 87
Or, ON ² = √87
Or, ON = 9.3 Cm
Therefore, the appropriate length from center to CD is 9.3 Cm.