Answer:
just click in the box it literally says
f(x) = ((x^2) / 3) + x, for f(6)
f(6) = ((6^2) / 3) + 6
Square 6
f(6) = (36 / 3) + 6
Divide 36 by 3
f(6) = 12 + 6
Combine like terms
f(6) = 18
Answer: 13 (and Sally will always be 3 years older than Jill)
Step-by-step explanation:
Let S and J stand for Sally and Jill's ages. We are told:
- (S-5) = (J-5)+3 [Sally is 3 years older than Jill was <u>5 years ago</u>] The 5 years ago is the reason for the (S-5) and (J-5) expressions.
If Jill is 10, how old is Sally?
(S-5) = (J-5)+3
(S-5) = (10-5)+3
S-5 = 8
S = 13
We actually don't really need an equation for solving this, other than the question asks us to write one. It doesn't matter how many years later, since Sally is 3 years older, she will always remain 3 years older, if we ignore the likelihood that the statement doesn't hold true for the period between their actual birthdays.
5 mg/kg twice a day for a 12 lb. cat
=5 mg/kg *2 doses/ day*12 lb * 0.4536 kg/lb
=10 mg/kg * 5.4432 kg / day
=54.432 mg / day
=54.432 / (50 mg/mL) /day
=54.432/50 mL / day
=1.088 mL / day
Answer: g = 7
Step-by-step explanation:
3+4=7 < i did that backwards but i hope u understand
