Given:
The arithmetic sequence is −15, −33, −51, −69.
To find:
The nth term of the arithmetic sequence.
Solution:
We have,
−15, −33, −51, −69
Here,
First term: a = -15
Common difference is
Now, nth term of an arithmetic sequence is
Substitute a=-15 and d=-18.
Therefore, the nth term of the given arithmetic sequence is .
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
Answer:
1.25
Step-by-step explanation:
20 ounces would be 1.25 pounds.
Please mark as brainliest! Thanks! If you need anymore help just let me know! :)
Answer:
D.(2, 2)
Step-by-step explanation:
- Staring point = (2, -4)
- Since he moved 6 units up, so, there will be change in only y-coordinate of the starting point and x-coordinate will remain unchanged.
- End point of the segment = (2, - 4 + 6) = (2, 2)
Answer:
9
Step-by-step explanation:
15(8-2)
15-(6)
9
