7x^4 + x^3 – 3x^2 + 5x – 2
Answer:
282.74 m^2
Step-by-step explanation:
Lateral surface area of the cylinder=2πrh
=2π(5)(9)
=282.74m^2
Solution
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Define the converse of a statement
The converse of a statement is formed by switching the hypothesis and the conclusion.
STEP 2: break down the given statements
Hypothesis: If M is the midpoint of line segment PQ,
Conclusion: line segment PM is congruent to line segment QM
STEP 3: Switch the two statements
Hence, the answer is given as:
If line segment PM is congruent to line segment QM, then M is the midpoint of line segment PQ,
Answer:
Step-by-step Solution:
<u>Let's simplify the equation to find the value of x.</u>
<u>[Simplify the Distributive property]</u>
<u>[Subtract 6 both sides]</u>
<u>[Solve the RHS]</u>
<u>[Divide -12 both sides to isolate the variable]</u>
<u>[Simplify the fraction]</u>
Hence, the value of x is -7/4.
Answer: The answer is 50980
Step by Step Explanation:
First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.
