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Ulleksa [173]
3 years ago
8

Leslie analyzed the graph to determine if the function it represents is linear or non-linear. First she found three points on th

e graph to be (–1, –4), (0, -3), and (2, 5). Next, she determined the rate of change between the points (–1, –4) and (0, -3) to be StartFraction negative 3 minus (negative 4) Over 0 minus (negative 1) EndFraction = StartFraction 1 Over 1 EndFraction = 1. and the rate of change between the points (0, -3) and (2, 5) to be StartFraction 5 minus (negative 3) Over 2 minus 0 EndFraction = StartFraction 8 Over 2 EndFraction = 4. Finally, she concluded that since the rate of change is not constant, the function must be linear. Why is Leslie wrong? The points (–1, –4), (0, –3), and (2, 5) are not all on the graph. The expressions StartFraction negative 3 minus (negative 4) Over 0 minus (negative 1) EndFraction and StartFraction negative 3 minus (negative 5) Over 2 minus 0 EndFraction both equal 1. She miscalculated the rates of change. Her conclusion is wrong. If the rate of change is not constant, then the function cannot be linear.
Mathematics
2 answers:
andrezito [222]3 years ago
8 0

Answer:

Its B :)

Step-by-step explanation:

motikmotik3 years ago
5 0
The answer is B

Explain:
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The complete statement is (d) Any rational root of f(x) is a factor of 9 divided by a factor of 12.

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The polynomial is given as:

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The first term in the above equation is 12 i.e. 12x^3, while the last term is 9

To determine the possible rational roots, we divide the factors of the last term i.e. 12 by the factors of the first term i.e. 12

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