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Phoenix [80]
3 years ago
6

Which of the following represents a moderate negative correlation? Explain.

Mathematics
2 answers:
AveGali [126]3 years ago
8 0
I think the answer us 0.5
sashaice [31]3 years ago
4 0

Step-by-step explanation:

The attachment above is a table summarizing everything.

so the answer should be - 0.5

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Jack earns $50 for washing cars on the weekend. He makes an average of $4.25 in tips per hour. Write the function of Joe's earni
Elena-2011 [213]
A function for this would be m = 50 + 4.25t. The $50 is the one time thing. We must multiply the tips by 6. 4.25 * 6 = 25.50. 50 + 25.50 is 75.50. Joe would make $75.50 after 6 hours.
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Step-by-step explanation:

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What is the slope of the line?
Katyanochek1 [597]

Answer:

1

Step-by-step explanation:

slope (k) is the rise over run of the line

a way of finding the slope if you have two dots of the line is:

k \:  =  \frac{y2 - y2}{x2 - x2}

here the dots that belong to the line that you can most easily see are:

A(-6,0)

B(0,6)

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6 0
2 years ago
G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =
Svetach [21]
Presumably you should be doing this using calculus methods, namely computing the surface integral along \mathbf r(u,v).

But since \mathbf r(u,v) describes a sphere, we can simply recall that the surface area of a sphere of radius a is 4\pi a^2.

In calculus terms, we would first find an expression for the surface element, which is given by

\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k
\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j
\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k
\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u

So the area of the surface is

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u
=-2\pi a^2(\cos\pi-\cos 0)
=-2\pi a^2(-1-1)
=4\pi a^2

as expected.
6 0
3 years ago
Nevaeh has $0.80 worth of nickels and dimes. She has a total of 11 nickels and dimes altogether. Graphically solve a system of e
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Answer:

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