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Bas_tet [7]
2 years ago
13

Suppose Q and Rare independent events. Find P(Q and R) if P(Q)= 7/15 and P(R)= 4/7.

Mathematics
1 answer:
VikaD [51]2 years ago
6 0

Answer:

4/15

Step-by-step explanation:

Independent events:

P(Q and R) = P(Q)×P(R)

P(Q and R) = 7/15 × 4/7

p(Q and R) = 4/15

I hope I've helped you.

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PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM
Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer:  {x = 1 , y=1, z=0

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2 years ago
Andy buys shoes that are on sale for 25% off the regular price. If the sale price is $36.45, what was the regular price of the s
Anettt [7]
She bought the shoe at a percent of 25
5 0
3 years ago
(50 points) What is the value of sin J for this triangle?
weqwewe [10]

Answer:

8/17

Step-by-step explanation:

right angle box means that area is the bottom

soh cah toa

hypotenuse is 17

hypotenuse is usually the biggest number

opposite is 8

sin is opposite/ hypotenuse

sin is 8/17

6 0
2 years ago
Which expression is equivalent to 10x2y + 25x2?
babymother [125]
10 x^{2} y +25 x^{2}  = 5 x^{2} ( \frac{10 x^{2} y +25 x^{2} }{5 x^{2} })  = 5 x^{2} ( \frac{10 x^{2} y}{5 x^{2} } +  \frac{25 x^{2} }{5 x^{2} } ) = 5 x^{2} ( \frac{2y}{1} +  \frac{5}{1} )

Answer A   5x² * ( 2y + 5)
7 0
3 years ago
Read 2 more answers
A+B=44<br> A : B is equvililent to 13 :8 <br> Please solve
Veronika [31]

Step-by-step explanation:

<h3>13:8</h3><h3>A=13x. B=8x</h3><h3>13x + 8x = 44</h3><h3> 21x=44</h3><h3> x=2.095</h3>
3 0
3 years ago
Read 2 more answers
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