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Olin [163]
3 years ago
11

Use addition to solve the Ix-y=6 ly=x-4

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

Ix-y=6, Ly=x-4

Step-by-step explanation:

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Anne has three more dollars than Freddy. Together they have $99. How many dollars does each have?
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Anne has 51. Freddy has 48.
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3 years ago
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What the answer is and how?
sladkih [1.3K]

Answer:

PerimeterFigure= pi*DIameter/2= 1.5*pi ft.

Step-by-step explanation:

The perimeter is the length of the figure, since we are dealing with an semi-circle, we can use the perimeter equation for a full circle and divide it by half.

Perimeter= 2pi*R= pi*Diameter.

Since Our figure is a semi circle, as we say earlier, we now will divide the above result by half.

PerimeterFigure= pi*DIameter/2= 1.5*pi ft.

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3 years ago
A molasses can is made with a cylindrical base having a radius of 6 cm, that is topped by a smaller cylindrical pouring spout wi
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Answer:

The total height of the can is 20cm

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A study of 35 golfers showed that their average score on a particular course was 92. The sample standard deviation was 5. We wan
svlad2 [7]

Answer:

t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322

Step-by-step explanation:

We have a sample of size n = 35, \bar{x} = 92 and s = 5. As we want to construct a 95% confidence interval to estimate the value of the true population mean \mu, we should use the pivotal quantity given by T = \frac{\bar{X}-\mu}{S/\sqrt{n}} which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322, i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that P(-2.0322\leq T\leq 2.0322) = 0.95 because of the simmetry of the t distribution.

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3 years ago
How would you do this question?
diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0
3 years ago
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