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Varvara68 [4.7K]
3 years ago
5

Determina en cada caso, si la función corresponde a una función lineal o a una función afín. a. Y = -5x b. Y = -3x – 2 c. Y = 2x

+ 4 d. Y = 1x/4 – 2
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Sabemos que una función lineal es de la forma:

f(x) = m*x

Mientras que una funcion afin es de la forma:

g(x) = m*x + n

Entonces para reconocer si una función es lineal o afín, simplemente debemos ver si tenemos un término constante o no (un término constante es un término que no está siendo multiplicado por la variable x).

a) y = -5*x

No tenemos término constante, entonces es una función lineal.

b) y = -3*x - 2

Acá tenemos un término constante igual a -2, entonces esto es una función afín.

c) y = 2*x + 4

Acá tenemos un término constante igual a 4, entonces esto es una función afín.

d) y = (1/4)*x - 2

Acá tenemos un término constante igual a -2, entonces esto es una función afín.

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Alisiya [41]
X/8 + 12 = 16 
start by subtracting twelve from both sides
x/8 + 12 = 16 
      - 12   -12
You're left with x/8 = 4
Multiply both sides by 8
8× x/8 = 4 ×8
Your answer is x = 32
If you need to simplify, the answer is 2. 


 
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3 years ago
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Answer:

B and D (

Step-by-step explanation:

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3 years ago
An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov
babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this.  This will give us the two times that the object is at exactly 500 meters.  The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using our values for a, b and c,

x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds.  This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0
3 years ago
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steposvetlana [31]
The answer is -6x^2 + 7x, or answer choice A.
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3 years ago
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A rectangular prism has a length of 114 centimeters, a width of 4 centimeters, and a height of 314 centimeters.
algol13
Hello!
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The volume of the prism is 143184 cm^3
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WORK: 114*4=456*314=143184
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Have a great day!
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3 years ago
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