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Varvara68 [4.7K]
3 years ago
5

Determina en cada caso, si la función corresponde a una función lineal o a una función afín. a. Y = -5x b. Y = -3x – 2 c. Y = 2x

+ 4 d. Y = 1x/4 – 2
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Sabemos que una función lineal es de la forma:

f(x) = m*x

Mientras que una funcion afin es de la forma:

g(x) = m*x + n

Entonces para reconocer si una función es lineal o afín, simplemente debemos ver si tenemos un término constante o no (un término constante es un término que no está siendo multiplicado por la variable x).

a) y = -5*x

No tenemos término constante, entonces es una función lineal.

b) y = -3*x - 2

Acá tenemos un término constante igual a -2, entonces esto es una función afín.

c) y = 2*x + 4

Acá tenemos un término constante igual a 4, entonces esto es una función afín.

d) y = (1/4)*x - 2

Acá tenemos un término constante igual a -2, entonces esto es una función afín.

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Write an equation and solve. Round to the nearest hundredth where necessary. What percent of 24 is 30?
garri49 [273]
30 = 100%

1 = 100/30 = 10/3 %

24 = 10/3 x 24 = 80%

Answer: 80%

7 0
3 years ago
Return to the credit card scenario of Exercise 12 (Section 2.2), and let C be the event that the selected student has an America
Nadya [2.5K]

Answer:

A. P = 0.73

B. P(A∩B∩C') = 0.22

C. P(B/A) = 0.5

   P(A/B) = 0.75

D. P(A∩B/C) = 0.4

E. P(A∪B/C) = 0.85

Step-by-step explanation:

Let's call A the event that a student has a Visa card, B the event that a student has a MasterCard and C the event that a student has a American Express card. Additionally, let's call A' the event that a student hasn't a Visa card, B' the event that a student hasn't a MasterCard and C the event that a student hasn't a American Express card.

Then, with the given probabilities we can find the following probabilities:

P(A∩B∩C') = P(A∩B) - P(A∩B∩C) = 0.3 - 0.08 = 0.22

Where P(A∩B∩C') is the probability that a student has a Visa card and a Master Card but doesn't have a American Express, P(A∩B) is the probability that a student has a has a Visa card and a MasterCard and P(A∩B∩C) is the probability that a student has a Visa card, a MasterCard and a American Express card. At the same way, we can find:

P(A∩C∩B') = P(A∩C) - P(A∩B∩C) = 0.15 - 0.08 = 0.07

P(B∩C∩A') = P(B∩C) - P(A∩B∩C) = 0.1 - 0.08 = 0.02

P(A∩B'∩C') = P(A) - P(A∩B∩C') - P(A∩C∩B') - P(A∩B∩C)

                   = 0.6 - 0.22 - 0.07 - 0.08 = 0.23

P(B∩A'∩C') = P(B) - P(A∩B∩C') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.4 - 0.22 - 0.02 - 0.08 = 0.08

P(C∩A'∩A') = P(C) - P(A∩C∩B') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.2 - 0.07 - 0.02 - 0.08 = 0.03

A. the probability that the selected student has at least one of the three types of cards is calculated as:

P = P(A∩B∩C) + P(A∩B∩C') + P(A∩C∩B') + P(B∩C∩A') + P(A∩B'∩C') +              

     P(B∩A'∩C') + P(C∩A'∩A')

P = 0.08 + 0.22 + 0.07 + 0.02 + 0.23 + 0.08 + 0.03 = 0.73

B. The probability that the selected student has both a Visa card and a MasterCard but not an American Express card can be written as P(A∩B∩C') and it is equal to 0.22

C. P(B/A) is the probability that a student has a MasterCard given that he has a Visa Card. it is calculated as:

P(B/A) = P(A∩B)/P(A)

So, replacing values, we get:

P(B/A) = 0.3/0.6 = 0.5

At the same way, P(A/B) is the probability that a  student has a Visa Card given that he has a MasterCard. it is calculated as:

P(A/B) = P(A∩B)/P(B) = 0.3/0.4 = 0.75

D. If a selected student has an American Express card, the probability that she or he also has both a Visa card and a MasterCard is  written as P(A∩B/C), so it is calculated as:

P(A∩B/C) = P(A∩B∩C)/P(C) = 0.08/0.2 = 0.4

E. If a the selected student has an American Express card, the probability that she or he has at least one of the other two types of cards is written as P(A∪B/C) and it is calculated as:

P(A∪B/C) = P(A∪B∩C)/P(C)

Where P(A∪B∩C) = P(A∩B∩C)+P(B∩C∩A')+P(A∩C∩B')

So, P(A∪B∩C) = 0.08 + 0.07 + 0.02 = 0.17

Finally, P(A∪B/C) is:

P(A∪B/C) = 0.17/0.2 =0.85

4 0
3 years ago
d(t)=750t/(t+12) where t is the age in years and d is the dosage. what is an expression for the rate of change of a child's dosa
Maksim231197 [3]
This just wants the derivative which you can solve for.
You can do this using a negative expononet or using ...the rational rule forget its name*.... you shoudl get 9000/(t+12)^2


*Quotient rule
3 0
3 years ago
If y=1/2 when x=2, find y when x=3, given that y varies directly with x
Lelu [443]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
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\begin{array}{llll}
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4 0
3 years ago
Angelo, age 40, is comparing the premium for a $125,000 whole life insurance policy he may take now and the premium for the same
Vesna [10]

The correct answer is <u><em>C.</em></u>

125000/20*2=12500, then round

Hope this helps!!!

8 0
2 years ago
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