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3 years ago

The probability for success of an event is P(A), and the probability of success of a second event is P(B). What is the

Mathematics

2 answers:

elena-s [515]3 years ago

8 0

Answer:

b I am sure because to x the number to the the probability and we don't know which ]h one so there is a 50% 50% chance for both.

Step-by-step explanation:

Kipish [7]3 years ago

3 0

Answer:

Option B - $P(A)\cdot P(B)$

Step-by-step explanation:

Given : The probability for success of an event is P(A), and the probability of success of a second event is P(B).

To find : What is the probability of both events occurring, in that order?

Solution :

The probability for success of an event is P(A).

The probability of success of a second event is P(B).

As the events are independent so the probability of both events occurring, in that order is $P(A)\cdot P(B)$

Therefore, Option C is correct.

The probability of both events occurring, in that order is $P(A)\cdot P(B)$

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2 years ago

Enter the ratio as a fraction in lowest terms 30 minutes to 27 minutes

vampirchik [111]

Step-by-step explanation:

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3 years ago

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Which equation cab be used to solve for x in the triangle below ?

Elis [28]

Answer:

Step-by-step explanation:

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3 years ago

2564.0 millimeters tall. If the boards are too long they must be trimmed, and if the boards are too short they cannot be used. A

Leokris [45]

Answer:

We conclude that the board's length is equal to 2564.0 millimeters.

Step-by-step explanation:

We are given that a sample of 26 is made, and it is found that they have a mean of 2559.5 millimeters with a standard deviation of 15.0.

Let $\mu$ = population mean length of the board.

So, Null Hypothesis, $H_0$ : $\mu$ = 2564.0 millimeters {means that the board's length is equal to 2564.0 millimeters}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 2564.0 millimeters {means that the boards are either too long or too short}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s }{\sqrt{n}} }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean length of boards = 2559.5 millimeters

s = sample standard deviation = 15.0 millimeters

n = sample of boards = 26

So, the test statistics = $\frac{2559.5-2564.0}{\frac{15.0 }{\sqrt{26}} }$ ~ $t_2_5$

= -1.529

The value of t-test statistics is -1.529.

Now, at a 0.05 level of significance, the t table gives a critical value of -2.06 and 2.06 at 25 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the board's length is equal to 2564.0 millimeters.

4 0

3 years ago

A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d

UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

= 10

5 0

3 years ago