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SIZIF [17.4K]
3 years ago
15

A fish tank is in the shape of an open glass cuboid 30 cm deep with a base 16 cm by 17 cm, these measurements being external. If

the glass is 0.5 cm thick and its mass is 3 g/cm3, find a the capacity of the tank in litres, and the mass of the tank in kg.​
Mathematics
1 answer:
omeli [17]3 years ago
8 0

Answer:

3.24 kg

Step-by-step explanation:

internal Vol = (30-0.5)(16-1)(17-1) = 7080 cm^3 = 7.08ltrs

external Vol= 30* 16* 17 = 8160cm^3 = 8.16ltrs

Vol of thickness = 8160 - 7080 = 1080cm^3

Mass of the tank= density * volume = 3*1080 = 3,240g = 3.24 kg

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Explain the differences (exponents)<br><br> -6^4 and (-6)^4
wel

Step-by-step explanation:

-  {6}^{4}  =  - 1296 \\  \\  (-  {6})^{4}  =  1296

The product of -6^4 is negative whereas the product of (-6) ^4 is positive.

7 0
3 years ago
Explain why 1 hundred 4 tens and 14 tens name the same amount.
artcher [175]
Because 14 tens is 10+4 tens
10 tens is a hundred
so 14 tens is a hundred + 4 tens
7 0
3 years ago
A rectangle is twice as long as it is wide. Its width is 5 1/2 cm. Find the perimeter of the rectangle.
kolezko [41]
5.5 × 2= 11

11 is the length.

perimeter= 11+11+5.5+5.5

The perimeter is 33 units.
5 0
3 years ago
There are 52 cards in a deck, and 13 of them are hearts. Four cards are dealt, one at a time, off the top of a well-shuffled dec
irga5000 [103]

Answer:

10.97%

Step-by-step explanation:

There are 52 cards.

13 of them, are hearts.

Then

52 - 13 = 39 cards are not hearts.

4 cards are drawn, we want to find the percent chance that the fourth card is a heart card, but no before.

So the first card can't be a heart card.

because the deck is well-shuffled, all the cards have the same probability of being drawn.

Then the probability of not getting a heart card, is equal to the quotient between the number of non-heart cards (39) and the total number of cards (52), then the probability is:

p₁ = 39/52

The second card also can't be a heart card, the probability is calculated in the same way than above, but now there are 38 non-heart cards and a total of 51 cards (because one card was already drawn) then the probability here is:

p₂ = 38/51

For the third card the reasoning is similar to the two above cases, here the probability is:

p₃ = 37/50

The fourth card should be a hearts card, the probability is computed in the same way than above, as the quotient between the number of heart cards in the deck (13) and the total number of cards in the deck (now there are 49 cards)

then the probability is:

p₄ = 13/49

The joint probability (the probability of these 4 events happening together) is equal to the product between the individual probabilities:

P = p₁*p₂*p₃*p₄

P = (39/52)*(38/51)*(37/50)*(13/49) = 0.1097

The percent chance is the above number times 100%

Percent =  0.1097*100% = 10.97%

3 0
3 years ago
Answer. it fast please​
mojhsa [17]

Answer:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

Step-by-step explanation:

Given

(\frac{6}{10})^3 * (\frac{5}{9})^2

Required

Solve:

(\frac{6}{10})^3 * (\frac{5}{9})^2

Simplify 6/10

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2

Express 9 as 3^2

(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2

Apply law of indices

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}

Express as a sing;e fraction

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}

Apply law of indices:

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}

(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}

5 0
3 years ago
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