Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.

For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253

For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913

Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)

8 0

2 years ago

Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?

mafiozo [28]

Answer:

13x = 39

x=3

y=10

5 0

2 years ago

6 apples 4 bananas 3 carrots cost 2.93$ 4 apples 4 bananas and 2 carrots cost 2.22$ 8 carrots cost 0.88$ how much is each item

GarryVolchara [31]

Answer:

Step-by-step explanation:

carrot = 0.11 $ .ie 0.88/8

3 0

2 years ago

5. Arrival problems usually follow a Poisson distribution, but in this case the time between arrivals of customers at a bank dur

Finger [1]

Answer:

0.5 or 50%

Step-by-step explanation:

For any given value of 'x' representing the time between arrivals of two customers. If 0 < x <120, then the cumulative distribution function is:

$\frac{x-0}{120-0}=\frac{x}{120}$

Therefore, the probability that the time between the arrivals of two customers will be more than 60 seconds is determined by:

$P(X>60) = 1 -\frac{60}{120}\\P(X>60) = 0.5$

The probability is 0.5 or 50%.

5 0

3 years ago