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liraira [26]
2 years ago
13

Help me please I don’t understand this question so please help?

Mathematics
1 answer:
Luba_88 [7]2 years ago
3 0

Answer:

11- All 0's are on the x and y planes

12- All positive points/numbers are where the x and y axis are both positive (Quadrant 1, 2, and 4)

13- All negative points/numbers would be wherever the x and y axis are negative (Quadrants 2, 3, and 4)

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4) Choose the correct inequality for this situation.
Ksenya-84 [330]

Answer:

B. 21x + 40 ≤ 124

Step-by-step Explanation:

Maximum amount budgeted = $124 (this means they can't spend more than this)

x = number of people

Cost per head = $21

Given that Mr Walter already spent $40, which is part of the money budgeted, the number of people that can go canoeing cam be expressed with the following inequality:

21x + 40 ≤ 124

(note: the amount total to be spent will either be equal to or greater than $124, because it's the maximum amount budgeted for spending).

6 0
3 years ago
What is the simplified form of 10,000x64 ?<br> O 5000x32<br> O 5000x<br> O 100x®<br> O 100x32
andrew-mc [135]

\large \boxed {\sf  \color{purple}Option \:  D) {100}^{32} }

  • \large\sf \sqrt{10,000 {x}^{64}}

  • \large \sf( {10}^{4}  \times  {x}^{64}) \frac{1}{2}

  • \large \sf \: 10 \frac{4}{2} \times x \frac{64}{2}

  • \large \sf \:  {10}^{2}  \times  {x}^{32}

  • \large \boxed{ \sf \red{{100}^{32}}}

<h3>Hope It's Helps</h3>
7 0
2 years ago
Read 2 more answers
Find the slope of each line
yuradex [85]
The slope is -2. this is because if you look at the graph it goes down 2 units and it goes right to the once so it’ll be -2/1 which equals -2.
4 0
3 years ago
A patio is in the shape of a square, with a lengh of 35 feet. You wish to draw a black line down one diagonal.
SashulF [63]

Answer:

a) 35√2

b) between 25 and 36 (5² and 6²)

c) 49.5 ft

7 0
3 years ago
What is the area of this composite shape?
NNADVOKAT [17]
Area of rectangle = 6 x 7 = 42
area of triangle = 1/2(3)(6) = 9

area of figure = 42 + 9 = 51

answer
51 <span>in²</span>
7 0
3 years ago
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