Answer:
-1.683
Step-by-step explanation:
Given :
Group 1 :
x1 = 667 ; n1 = 10 ; s1 = 20
Group 2 :
x2 = 679 ; n2 = 14 ; s2 = 15
The test statistic assuming equal variance :
x1 - x2 / √[Sp² * (1/n1 + 1/n2)]
sp² = [(n1 - 1)*s1² + (n2 - 1)*s2²] ÷ (n1 + n2 - 2)
Sp² = [(10 - 1)*20² + (14 - 1)*15²] = 296.59
Test statistic =
(667 - 679)/ √[296.59 * (1/10 + 1/14)]
-12 / 7.1304978
Test statistic = - 1.682
The mode would be 17, it’s the number that appears the most. I’m not rewriting it though
Answer:
The answer is 1st point
Step-by-step explanation:
(12x²+4x-5)-(9x²-9x+1)
= 12x²+4x-5-9x²+9x-1
= 3x²+13x-6
Answer:
Find the function of two points first. Then check whether the third point is on it
Answer:
The amount of gold used in a 200 g 14 gold bracelet is 116 g.
Step-by-step explanation:
Since a 14 karat jewell is stated to have aproximally 58 % of it's weigh in gold we need to take the total weigh of the jewel in question and find that percentage of it's weigh. In order to find that percentage we'll first convert that number into a decimal, we do that by dividing it by 100, so we have 58% = 58/100 = 0.58 we can multiply this value by the weigh of the jewel to find the amount of gold used. So we have:
gold used = total weigh*0.58 = 200*0.58 = 116 g
