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LenKa [72]
2 years ago
14

Which of the following is most likely the next step in the series?

Mathematics
2 answers:
4vir4ik [10]2 years ago
6 0
I’m thinking probably c
Lemur [1.5K]2 years ago
3 0
B. :))))))))))))))))))))
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A triangle has an area of 36 cm². The base and height are scaled by a factor of 5.
ahrayia [7]
Triangle Area = .5 * (base * height)
36 = (base * height) / 2
So let's say base = 9 height 8
If base and height are scaled by a factor if 5 than
base = 45 height 40 and
area = .5 * (45 * 40)
area = 900

Basically, the area increases by a factor of 25.
The base increases by 5 and the height increases by 5 so the area increases by 5*5 = 25

4 0
3 years ago
Manuel buys 7.9 pounds of strawberries. Each pound costs $3.89. Which expression gives the best estimate of the cost of the stra
topjm [15]
The options you gave are extremely confusing, but if you round 7.9 it is 8, and if you round $3.89 it is $4. Therefore, the best estimate would be 8•$4, or $32
7 0
3 years ago
Read 2 more answers
3, 12, 48, 192, 768, . . .
Sav [38]
The answer would be the sequence has a common ratio of 4.
The explanation for this would be:
To get the common ratio for get the simplest form of the two numbers, so 12/3 = 4 and 48/12 = 4So we know that their common ratio is 4.
To check:
3 x 4 = 12
12 x 4 = 48
48 x 4 = 192
192 x 4 = 768
7 0
3 years ago
How much is 290 dimes
sweet [91]
$29.00 and you can also multiply too is is a cool way
7 0
2 years ago
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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
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