Question

You are making the kite shown at the right from

Answer 1

Answer:

a. Side lengths of ΔBEX are;

BE = 15 ft.

EX = 12 ft.

BX = 9 ft.

b. Side lengths of XEFY are;

XY = 6 ft.

EX = 12 ft.

FY = 7.5 ft.

EF = 7.5 ft.

c. Side lengths of YFGZ are;

GZ = 6 ft.

FY = 7.5 ft.

YZ = 2 ft.

FG = 2.5 ft.

d. Side length of triangle ZGC

GZ = 6 ft.

GC = 10 ft.

ZC = 8 ft.

Step-by-step explanation:

The given parameters are;

XY : YZ : ZC  is 3 : 1 : 4

The length of BC = 25 in.

The length of EB = 15 in.

Therefore, EC = √(BC² - EB²) = √(25² - 15²) = √400 = 20 in.

Given that EX║ YF║GZ, we have;

EF : FG : GC is 3 : 1 : 4 (Parallel lines cut segments in equal proportions)

Therefore;

EF = 20 × 3/(3 + 1 + 4) = 7.5 ft.

FG = 20×1/8 = 2.5 ft.

GC = 20×4/8 = 10 ft.

EC/EX = BC/EB

20/EX = 25/15

EX = 15×20/25 = 12 ft.

XC = √(EC² - EX²) = √(20² - 12²) = 16

XY : YZ : ZC  is 3 : 1 : 4

Therefore;

XY = 16 × 3/8 = 6 ft.

YZ = 16 × 1/8 = 2 ft.

ZC = 16 × 4/8 = 8 ft.

GZ = √(GC² - ZC²) = √(10² - 8²) = 6

Area of triangle ΔZGC = 1/2×6×8 = 24 ft²

XB = BC - XC = 25 - 16 = 9 ft.

Area of ΔBEX = 1/2×9×12 = 54 ft²

a. Side lengths of ΔBEX are;

BE = 15 ft.

EX = 12 ft.

BX = 9 ft.

FY = √(FC² - YC²) = √((10 + 2.5)² - (8 + 2)²) = 7.5 ft.

Area of YFGZ = (GZ + FY)/2 × YZ = (6 + 7.5)/2 × 2 = 13.5 ft²

Area of YFGZ = 13.5 ft²

Area of XEFY = XY × (EX + FY)/2 = 6 × (12 + 7.5)/2 = 58.5 ft.²

b. Side lengths of XEFY are;

XY = 6 ft.

EX = 12 ft.

FY = 7.5 ft.

EF = 7.5 ft.

c. Side lengths of YFGZ are;

GZ = 6 ft.

FY = 7.5 ft.

YZ = 2 ft.

FG = 2.5 ft.

d. Side length of triangle ZGC

GZ = 6 ft.

GC = 10 ft.

ZC = 8 ft.

Answer 2

I wouldn’t know sorry