one the first one the sign flipped because you divided by a negative number, on the third one it was all real numbers because the coefficients of n (which was "3") are equal and 3n+15 is greater than or equal to 3n+8 no matter what number you put in
Answer:
(a) 2 feet.
(b) 2 feet.
Step-by-step explanation:
We have been given that the velocity function
in feet per second, is given for a particle moving along a straight line.
(a) We are asked to find the displacement over the interval
.
Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.




Using power rule, we will get:
![\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%5Cright%5D%20%5E4_1)
![\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5Cright%5D%20%5E4_1)

Therefore, the total displacement on the interval
would be 2 feet.
(b). For distance we need to integrate the absolute value of the velocity function.


Since square root is not defined for negative numbers, so our integral would be
.
We already figured out that the value of
is 2 feet, therefore, the total distance over the interval
would be 2 feet.
Answer:
g(f(2)) = 11
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x - 2
g(x) = x² - 5
<u>Step 2: Find g(f(2))</u>
f(2)
- Substitute in <em>x</em>: f(2) = 3(2) - 2
- Multiply: f(2) = 6 - 2
- Subtract: f(2) = 4
g(f(2))
- Substitute in <em>x</em>: g(4) = 4² - 5
- Exponents: g(4) = 16 - 5
- Subtract: g(4) = 11
Cats can also be any size like it can 80cm 60cm, depends on the size