All categories

3 years ago

Is 20% greater than 0.02

Mathematics

1 answer:

Ket [755]3 years ago

6 0

Yep it is greater. Hope this helps

You might be interested in

I can't figure out number 7.

Levart [38]

It would take just over 6 minutes assuming it takes him 2. 6 minutes to wax a single square inch somehow.

8 0

3 years ago

Jefferson is plotting the vertices of an isosceles right triangle on a coordinate graph. He has plotted the two points shown. Wh

DENIUS [597]

Answer: (-2 -9)

Step-by-step explanation:

Have no time

3 0

2 years ago

5x - 18

Kobotan [32]

Make sure to simplify

6 0

2 years ago

hus, D satisfying (ABC)DequalsI exists. Why does the expression for D found above also satisfy D(ABC)equalsI, thereby showing

Assoli18 [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

First Question

Option A is correct

Second Question

Option C is correct

Third Question

$D = A^{-1} * B^{-1} * C^{-1}$

Fourth Question

So substituting for D in (ABC) D = I

$(ABC) * A^{-1} * B^{-1} * C^{-1} = I$

$I = I$

This proof that ABC is invertible

Step-by-step explanation:

From the question we are told that

A , B and C are invertible which means that $A^{-1} , B^{-1}, C^{-1}$ exist

Now

From the question

(ABC) D = I

Where I is an identity matrix

Now when we multiply both sides by $A^{-1}$ we have

$A^{-1} A BCD = A^{-1} * I$

$IBCD = A^{-1}$

Now when we multiply both sides by $B^{-1}$ we have

$B^{-1 } *I BCD = A^{-1} * B^{-1}$

$I CD = A^{-1} * B^{-1}$

Now when we multiply both sides by $C^{-1}$ we have

$C^{-1} * I CD = A^{-1} * B^{-1} * C^{-1}$

$I D = A^{-1} * B^{-1} * C^{-1}$

$D = A^{-1} * B^{-1} * C^{-1}$

So substituting for D in the above equation

$(ABC) * A^{-1} * B^{-1} * C^{-1} = I$

$I = I$

This proof that ABC is invertible

4 0

2 years ago

Help fast please<br> i have no idea what to do in math so i need help

siniylev [52]

Answer:

see the attachment photo!

5 0

1 year ago