Commercial jet's speed = 2x-162 (plug this in the equation below)
Private jet's speed = x
Equation:
10(x) = 8(2x-162)
10x = 16x - 1296
6x = 1296
x = 216 (Private jet's speed)
Take the first equation and plug x value in;
2x-162
2(216) - 162 = 270 ( Commercial jet's speed)
Answer:
C
Step-by-step explanation:
∠ TUL + ∠ LUV = ∠ TUV , substitute values
x + 16 + 11x = 172 , that is
12x + 16 = 172 ( subtract 16 from both sides )
12x = 156 ( divide both sides by 12 )
x = 13 → C
STEP 1:
determine equations needed
x= # of $10 tickets
y= # of $14 tickets
QUANTITY EQUATION
x + y= 800
COST EQUATION
$10x + $14y= $9,040
STEP 2:
multiply quantity equation by -14
-14(x + y)= -14(800)
-14x - 14y= -11,200
STEP 3:
add new quantity equation in step 2 to cost equation of step 1 to solve for x using elimination
-14x - 14y= -11,200
10x + 14y= 9040
y term cancels out
-4x= -2160
divide both sides by -4
x= 540 ten dollar tickets
STEP 4:
substitute x value in step 3 into either original equation
x + y= 800
540 + y= 800
subtract 540 from both sides
y= 260 fourteen dollar tickets
ANSWER: There were 540 $10 tickets and 260 $14 tickets sold.
Hope this helps! :)
One solution because it only has one answer that can come out if those properties. If you add the -3 to -6 it will make it 6=12 -3x. Subtract the 12 it will be -6=-3x divide by -3 and x=2
