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3 years ago

Rose rolled a regular 6-sided dice. What is the probability she rolled an even number?

Mathematics

2 answers:

kherson [118]3 years ago

7 0

Answer:

$\frac{3}{6}$

Step-by-step explanation:

uysha [10]3 years ago

6 0

3/6 chance :) hope this helps!!

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P= -24 q= 12 r= -6 a. (pxq):(q+r) b. (pxr):(r-q) what the answer?

kolezko [41]

Step-by-step explanation:

a. ( p × q ) ( q + r )

= ( -24 × 12 ) ( 12 + -6 )

= 288 × 18

= 5184

b. ( p × r ) ( r - q )

= ( -24 × -6 ) ( -6 - 12 )

= ( 144 ) ( -18 )

= -2592

5 0

3 years ago

Lynda cuts a piece of wood for a project. The first cut is shown and can be represented by the equation y=1/4x-5.The secend cut

Svetradugi [14.3K]

Since the second line is parallel to the first, it will have the same slope. The y-intercept of the new line is 4 (because of the coordinates given) so the equation of Lynda's second cut is y = 1/4x + 4 which is choice C

4 0

3 years ago

Read 2 more answers

Someone please helppp

KiRa [710]

Answer:

2,16 16,2

Step-by-step explanation:

probally wrong

7 0

3 years ago

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Find the solution of the given initial value problem: y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$