The markup is 8%, meaning it costs 8% more.
The starting price is 100%.
Therefore, the markup is 108% of $12.
If we multiply 12 by 108% (1.08), we will get our answer of $12.96
The calculation uses the accumulated daily balance method (ADB).
We assume the statement is based on calendar month (rare!).
George owes $500 from beginning to end of June, so 30 days out of 30.
Interest accrued is 500*0.013*30/30=$6.50.
He also owes $2000 from June 12 to June 30, so 19 days inclusively.
Interest accrued is $2000*.013*(19/30)=16.47
Total interest at the end of the month=$6.50+$16.47=$22.97
Answer:
About 4.
Step-by-step explanation:
It is actaully 3.95 but if you were rounding and in fraction form, it would be four! Hope this helps!
Answer:
$2191.12
Step-by-step explanation:
We are asked to find the value of a bond after 10 years, if you invest $1000 in a savings bond that pays 4% interest, compounded semi-annually.
, where,
,
r = Rate of return in decimal form.
n = Number of periods.
Since interest is compounded semi-annually, so 'n' will be 2 times 10 that is 20.
Therefore, the bond would be $2191.12 worth in 10 years.
The distance between town X and Town Y is equal to the difference between the distance between Town X and Town Z and the distance from Town Y and Town Z. Mathematically
d (X-Y) = d (X-Z) - d(Y-Z)
Substituting,
d(X-Y) = 57 miles - 28 miles = 29 miles
Thus, the distance from Town X to Town Y is 29 miles.
