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cricket20 [7]
3 years ago
8

Which expression is equivalent to 2(a + 2b) - a - 2b?

Mathematics
2 answers:
Margarita [4]3 years ago
8 0

Answer:

a + 2b

Step-by-step explanation:

To find the equivalent of the given expression, we must open up the parenthesis by multiplying each element in the parenthesis by 2, we would then collect like terms and simplify the algebraic expression.

2(a + 2b) - a - 2b

= 2a + 4b - a - 2b

= 2a - a + 4b  - 2b

= a + 2b

Free_Kalibri [48]3 years ago
4 0

The correct answer is D) a+2b.

Hope it helps!

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The sum of m and n is 32, and the value of m is three times the value of n. what is the value of m and n?
inn [45]

Answer:

The correct set of equations is C.

Step-by-step explanation:

m + n = 32

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We have 4n = 32, so n = 8 and m = 24.

4 0
1 year ago
The maximum value of 12 sin 0-9 sin²0 is: -​
jeka57 [31]

Answer:

4

Step-by-step explanation:

The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)

If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0

However, I will assume you meant the angle to be \theta rather than 0 which makes sense and proceed accordingly

We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0

The original function is

f(\theta) = 12sin(\theta) - 9 sin^2(\theta)

Taking the first derivative of this with respect to \theta and setting it equal to 0 lets us solve for the maximum (or minimum) value

The first derivative of f(\theta) w.r.t \theta is

                        12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right)

And setting this = 0 gives

12\cos\left(\theta\right)-18\cos\left(\theta\right)\sin\left(\theta\right) = 0

Eliminating cos(\theta) on both sides and solving for sin(\theta) gives us

sin(\theta) = \frac{12}{18} = \frac{2}{3}

Plugging this value of sin(\theta) into the original equation gives us

12(\frac{2}{3}) - 9(\frac{4}{9} ) = 8 - 4 = 4

This is the maximum value that the function can acquire. The attached graph shows this as correct

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