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3 years ago

Please help, no guessing. It would be great if you could explain, too.

2 answers:

6 0

a retired dentist, they would have experience and would understand what would be better for patients and all others who are learning. sorry if it wasn't the best, that's all I have. have a wonderful afternoon

Otrada [13]3 years ago

4 0

A retired dentist. Probably to get benefits or something like that.

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A scientist plants two rows of corn for experimentation. She puts fertilizer on row 1 but does not put fertilizer on row 2. Both

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Explanation:

I hope it helps choose me the brainest

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3 years ago

The followers of Guru Nanak ate in thecommon kitchen called langar. true or false

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true

Explanation:

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How should supermarket associates respond when a customer asks them a question in a rude manner? Let the customer know that he/s

Luden [163]

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An associate should continue to smile and try to be of some help in this type of situation.

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3 years ago

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Tju [1.3M]

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3 years ago

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I can’t figure this problem out

Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

$\int\limits^4_1 {(3f(x)+2)} \, dx$

So lets break this up into two different integrals that represent the same area.

$\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx$

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

$\int\limits^4_1 {f(x)} \, dx$

But since we have these values we can say that:

-3 - 2 = -5

Which means that $\int\limits^4_1 {f(x)} \, dx$ = -5

So now we can evaluate $\int\limits^4_1 {(3f(x)+2)} \, dx$

Lets first break up our integrand into two integrals

$\int\limits^4_1 {(3f(x)+2)} \, dx$ = $3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx$

Now we can evaluate this:

We know that $\int\limits^4_1 {f(x)} \, dx$ = -5

So:

$3(-5)+2[x]$ where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

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3 years ago